SURF示例源码

逐步回归算法程序，可以实现中间结果的任意输出-Stepwise regression algorithm procedure can be achieved between the results of any output

误差分析的方法有多种，例如，威点逊（J. H. Wilkison）针对的计算机的浮点运算提出的“向后误差分析”，这是一种先验估计误差的方法，较以往的“向前误差分析”在矩阵运算的舍入误差估计上有较好的结果，以而使矩阵的误差分析获得了突破性的进展，使不少用向前误差分析难于判定可靠性的数值方法获得新的进展。-error analysis by a number of means, for example, Granville point Morrison (J. H. Wilkison), referring to a computer"s floating-point operations "backward error analysis," This is a priori estimation error method, compared to the previous "Forward Error Analysis" in the matrix computation Rounding error a better estimate on the results of a matrix so the error analysis of a breakthrough in the progress, many with forward error analysis difficult to determine the reliability of numerical methods to achieve new progress.

最小二乘法计算程序-least squares method procedures

Hash算法C#实现-Hash Algorithm C#

分段算法的程序，很好的。绝对简练-Segmentations procedures very well. Absolutely concise

采用vc代码编写的，热电阻和热电偶的查询软件，适合工程上的一个小软件，可以实现8中类型的热电偶对应的电阻值查询，基本上包含了全部可能用到的工程上的热电偶

雅可比算法的算例程序，用简单明了的计算过程展示了雅可比算法的C设计过程。-Jacobi algorithm example program, with a simple and straightforward calculation shows C Jacobi algorithm design process.

分支定界的0/1背包问题-branch delimitation of the 0/1 knapsack problem

倒酒问题描述： 设有两个能装8两的酒杯（称为１号，２号）装满了酒, 和1个能装3两的空酒杯（称为３号）, 问怎样用这3个酒杯向4个人 敬酒, 使得每个人都喝4两酒. 要求： 用程序计算出可行方案。 输入： 无 输出： 每一步决策．-down quite Problem description : two can be loaded with two of the eight glasses (known as 1, 2) filled with the wine, and one can hold three two empty glasses (known as the 3rd) and asked how to use it three to four glasses and toast the individual, so that each person maximum servings of both types 4 2 liquor. Request : procedures calculated options. Input : None output : each step of the decision-making.

主旨表遗传算法-keynote table GA