Simple solution ADC , every 500ms 1 sample and sending 8 bit value by software U...

针对fidelix模块的测试软件源代码,通过串口,对fidelix(cdma模块)进行控制和检测.-against fidelix test software module source code, serial, right fidelix (cdma modules) for control and testing.

采用美国adi公司的bf系列，基于bf533的ez-kit平台的mmc和sd的读写功能的代码-Adoption of the United States adi

一个迷你的com通讯程序，是用win32asm写的。功能全面-a program made by win32asm

f2812串口通信接口B口，c语言,中断-f2812 serial communication interface B port, c language, interruption of

通过串口接收到外部发来的命令,来控制8路继电器的开关-Received through the serial port to an external command sent to control the 8-way relay switch

UART code which tells the function and provide a lab for UART-UART code

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NMEA解析，重组 函数源代码！ 能够根据格式符自定义输出，方便扩展-NMEA parsing, restructuring of the function the source code! Be able to customize the output according to format operators to facilitate the expansion of

这是非常有挑战性的题目。对于用户输入的任意一个平面函数f(x)，绘制出其函数曲线。这里最关键的技术难点就是如何实现计算表达式的值。在《编译原理》和《数据结构》的书中，都有对表达式运算方法的论述。说实在的，在编译型计算机语言中实现对用户输入表达式的运算是非常困难的。需要对表达式进行扫描，去括号，按照运算符的优先级生成2叉树，然后遍历该树生成逆波兰表达式，再然后通过栈的方法进行运算。如果在表达式中再包含有函数的话......描述起来都麻烦，更不要说用程序实现了:-(-This is a very challenging issue. For user input an arbitrary planar function f (x), mapping out its function curves. Here the most critical technical problems is how to achieve calculated the value of the expression. "Compiling Principle" and "data structure," the book, have right of expression Operational discussed. Indeed, the computer language compiler to achieve expression of the user input operation is very difficult. Need to scan expression to the brackets, in accordance with the priority Operators Generation 2-ary tree, and then traverse the tree generated reverse Polish expression, and then through the stack approach to computing. If the expression again contains the function described ...... these are trouble, not to mention t

用于开发税务票据管理的软件，可以打印，生成报表-tax bills for the development of the management software, print, generate statements