图像拼接融合算法

ICEM CFD基础教程，学习流体力学的朋友可以参考。-ICEM CFD Basic Course, learning hydromechanics friends can refer to.

素数环： 把从1到10这10个数摆成一个环，要求相邻的两个数的和是一个素数。 〖问题分析〗 这是一道回溯的题目。从1开始，每个空位有9种可能，每种可能加入约束条件即可 1.与前面所有的数不重复 2.与前一个数和为素数（最后一个和第一个也要满足）。 〖算法流程〗 1、数据初始化； 2、递归填数： 判断第J种可能是否合法；  A、如果合法：填数；判断是否到达目标（10个已填完）： 是，打印结果；不是，递归填下一个；  B、如果不合法：选择下一种可能；-Prime Central: 1-10 from 10 the number of put this into a ring, asked the two adjacent numbers and is a prime number. 〗 〖Analysis is a retrospective this topic. From 1 year, 9 out of every space possible, each may be bound by the conditions of accession to 1. And in front of all the number of non-repetition, 2. With a few and for a prime number (the last and the first to meet). 1〗 〖algorithm processes the data to initialize 2, fill in the number of recursion: first to determine the legality of J possible A, if the legitimate: the number of Reclamation to determine whether the target (10 have been completed): Yes, print the results of not, fill in the next recursive B, if not legitimate: a possible alternative

用matlab仿真对光谱进行定标和很好的一个随机数发生器-Matlab simulation of the spectrum used for calibration and a very good random number generator

#include "string.h"  #include   #include   #define M 5  #define N 3  #define FALSE 0  #define TRUE 1  银行家如何进行投资的简单算法

小波分解图像使图像分为低频和高频信息，通过这种方法可以增强图像的清晰度

用差分方法求解沃尔泰拉方程，此处为一个变元的方程，由于该方程同时含有微分和积分，一般求解有一定的困难。-use of the finite difference method for Volterra equation here as a variable element of the equation, As the same time contain differential equations and integral, the general solution is definitely difficult.

农夫过河问题源代码2-farmer across the river source code two issues

摄影测量中单独像对立体前交的算法实现，挺有用的-Photogrammetry separate ago as a three-dimensional reference to the algorithm, quite the

using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; using System.Drawing.Drawing2D; using System.Threading;  namespace WinRandomPI {     public partial class GetPIValue : Form

解开汉诺塔谜题，理解递归原理。 新手作品。