快速傅立叶变换，非常简洁快速。测试与mablab中快速傅立叶变换效果相当

《SM2椭圆曲线公钥密码算法》分为四个部分： ──第1部分：总则 ──第2部分：数字签名算法 ──第3部分：密钥交换协议 ──第4部分：公钥加密算法

C_algorithm2nd.pdf C语言的算法合集 欢迎下载ginger547的算法系列资料-C_algorithm2nd.pdf C language algorithms Collection ginger547 welcome to download the information algorithm Series

MP3播放器： 利用API函数[mciSendString]可以轻松实现MP3音乐文件的播放。下面这段程序实现了MP3播放的大部分常规操作，对其稍加修改，做一个100KB大小的MP3播放器轻而易举 启动VB程序，在窗体上放置6个命令按钮，三个标签，一个公用对话框、一个进度条、一个状态栏和一个计时器，窗本的布置请参考附图 按钮"Open MP3 File"是用来打开对话框选择MP3文件，其他5个按钮分别为Play(播放)、Pause(暂停)、Stopplay(停止播放)、Back(向后跳跃)、Prew(向前跳跃)。Label1用来表示歌曲当前时间；label2放在时度条的最左边，Caption属性为"00：00"；lable3放在时度条的右边，用来表示歌曲总长。-MP3 player : API function [mciSendString] can easily MP3 music player. Below this program of the MP3 player most of the conventional operation, its slightly modified, so the size of a 100KB MP3 player easily activated VB procedures, the forms to place orders six buttons, three label, a common dialog, a progress of a status bar and a 000 timer, the window layout of the buttons refer to the attached map. "MP3 File Open" is used to open the dialog box choose MP3 files, the other five buttons for Play (player), Pause (suspended), Stopplay (Cessation of players), Back (backwards jump), Prew (leap forward). Label1 songs said to the current time; Label2

一个比较简单的算法程序。输入一些数，计算后按照矩阵的形式输出。设了三个数组a[]，b[]，c[]。分别实现c[]=a[]+b[]，c[]=a[]-b[]，c[]=a[]*b[]。-a relatively simple procedure of the algorithm. The importation of some few, calculated in accordance with the matrix in the form of output. Established three array a [], [] b, c []. C respectively, to achieve a = [] [] [] b, c = a [] []- [] b, c [] [] = a* b [].

我自己写的一个24点计算器希望你能帮我改正很多。有什么更好的算法，还请指导！

绘制螺纹的MATLAB程序，对于生成螺纹管等几何体较为重要-A MATLAB program can draw bolt pattern, and is more important to produce bolt pattern pipe and other geometry body

实现Hough Transform检测直线和圆的代码，通过自适应画线和圆，能够找到当前的圆和直线位置

基于无迹卡尔曼滤波的室内移动系统的性能强化，比较经典。-Unscented Kalman filter-based indoor mobile systems to strengthen performance, compare the classic.

正整数x 的约数是能整除x 的正整数。正整数x 的约数个数记为div(x)。例如，1，2，5，10 都是正整数10 的约数，且div(10)=4。设a 和b 是2 个正整数，a≤b，找出a 和b之间约数个数最多的数x。 对于给定的2 个正整数a≤b，编程计算a 和b 之间约数个数最多的数。 数据输入 输入数据由文件名为input.txt的文本文件提供。文件的第1 行有2 个正整数a和b。 结果输出 程序运行结束时，若找到的a 和b 之间约数个数最多的数是x，将div(x)输出到文件output.txt中。 输入文件示例 输出文件示例 input.txt output.txt 1 36 9 -Positive integer x can be about a few of the positive integer x divisible. Positive integer x the approximate number recorded as the number of div (x). For example, 1,2,5,10 are about 10 positive integer number, and div (10) = 4. Set a and b are two positive integers, a ≤ b, to find a and b between about a few number of the largest number of x. For a given two positive integers a ≤ b, Programming calculated a and b between about a few number of the largest number. Data entry input data from the document text file named input.txt provide. File line 1 has two positive integers a and b. The results run the end of the output, if found between a and b of about a few number o

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