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vhdl按键检测
基于vhdl的按键检测程序。可以有效消除抖动(vhdl key dectect program)
- 2018-02-26 23:48:35下载
- 积分:1
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spi
VHDL实现SPI功能源代码
-- The SPI bus is a 3 wire bus that in effect links a serial shift
-- register between the "master" and the "slave". Typically both the
-- master and slave have an 8 bit shift register so the combined
-- register is 16 bits. When an SPI transfer takes place, the master and
-- slave shift their shift registers 8 bits and thus exchange their 8
-- bit register values.(SPI realize the functional VHDL source code The SPI bus is a 3 wire bus that in effect links a serial shift register between the )
- 2021-04-29 10:58:43下载
- 积分:1
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sanjose_hdlcon
FFT implementation using C program
- 2014-02-11 21:01:40下载
- 积分:1
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用FPGA实现数字锁相环,开发环境为ISE
用FPGA实现数字锁相环,开发环境为ISE-Using FPGA digital phase-locked loop, development environment for ISE
- 2022-06-22 05:34:34下载
- 积分:1
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Dec_mul
时间同步后即可确定每帧数据的起始位置,这样就能完整的截取下每一帧。但是,数据中还带有频偏信息。在常规的通信系统中,多普勒很小仅仅会带来很小的频偏,但是在大多普勒的情况下,频偏将非常大,20马赫的速度将会带来将近34K的频偏。因此,如何很好的纠正频偏即为本系统的难点。
OFDM中,我们将大于子载波间隔倍数的频偏称为整数倍频偏,而将小于一个子载波间隔的频偏称为小数倍频偏。频偏矫正精度只要能保证小于十分之一倍的子载波间隔,频偏就不会对均衡和解调造成影响。本文中我们借鉴这种思想,由于硬件资源限制,我们将在接收端做64点FFT,即相当于将频域划分为64份,我们将小于 的频偏称为小数倍频偏,将 整数倍的频偏称为整数倍频偏。本程序即基于SCHIMDL经典方法完成小数倍频偏纠正(After time synchronization can determine the starting position of each frame data, so you can complete the interception of each frame. However, in the data with frequency information. In conventional communication systems, doppler small will bring only small deviation, but in the case of most of the doppler, frequency PianJiang is very large, 20 Mach speed will lead to deviation of nearly 34 k. Therefore, how to good to correct deviation is the difficulty of this system.
OFDM, we will be bigger than the sub-carrier spacing ratio of frequency deviation is called the integer frequency offset, and the interval will be less than a child carrier frequency offset is called decimal frequency doubling. Deviation is less than one over ten times as long as can guarantee accuracy of sub-carrier spacing, deviation will not affect balance and demodulation. This article, we draw lessons from the idea, due to the limited hardware resources, we will do 64 points FFT at the receiving end, which is equ)
- 2013-12-26 18:00:24下载
- 积分:1
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Xcell1
W elcome to X CELL, the new
Xilinx customer newsletter.
By sending us your development
system registration card you automatically
became n charter subscriber
to this quarterly publication. It is our
intent to make this an informative,
easy to read, responsive and-hopefully-
interactive newsletter. We
want to supply you with early and
correct information, tell you about
the status of our products and about
our plans, about bugs and their workarounds,
give you applications ideas
and convey to you some of the en thusiasm
that we feel for our Programmable
Gate Arrays.
If you have questions or suggestions,
please send them to me. II Letters
to the Editor make a newsletter
more lively.
Peter Alfke, Editor
- 2014-12-25 01:07:59下载
- 积分:1
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《CPLDFPGA verilog DA0832调控
verilog da0832 cpldfpga control-verilog da0832 cpldfpga control
- 2022-12-07 05:55:03下载
- 积分:1
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Modulation
产生长度为100的随机二进制序列
发送载波频率为10倍比特率,画出过采样率为100倍符号率的BPSK调制波形(前10个比特) ,及其功率谱
相干解调时假设收发频率相位相同,画出x(t) 的波形,假设低通滤波器的冲激响应为连续10个1(其余为0),或连续12个1 (其余为0) ,分别画出两种滤波器下的y(t),及判决输出(前10个比特)
接收载波频率为10.05倍比特率,初相位相同,画出x(t) 的波形,假设低通滤波器的冲激响应为连续10个1,画出两种滤波器下的y(t),及判决输出(前20个比特)
采用DPSK及延时差分相干解调,载波频率为10倍比特率,画出a, b, c, d点的波形(前10个比特)
DPSK及延时差分相干解调,载波频率为10.25倍比特率时,画出a, b, c, d点的波形(前10个比特)
DPSK及延时差分相干解调,载波频率为10.5倍比特率时,画出a, b, c, d点的波形(前10个比特)
(Produce random binary sequence of length 100
The transmission carrier frequency is 10 times the bit rate, draw a sampling rate of 100 times the symbol rate of the BPSK modulation waveform (first 10 bits), its power spectrum
Coherent demodulation of assuming the same as the phase of the transmitting and receiving frequencies, and draw the waveform x (t), assuming that the impulse response of the low pass filter 10 consecutive 1 (the remainder is 0), or 12 consecutive 1 (the remainder is 0), y (t) is drawn under the two filters respectively, and the decision output (10 bits)
The received carrier frequency is 10.05 times the bit rate, the same initial phase, draw the waveform x (t), assuming that the impulse response of the low pass filter of 10 consecutive 1, shown under two filter y (t), and decision output (20 bits)
DPSK and delay differential coherent demodulation, the carrier frequency is 10 times the bit rate, draw a, b, c, d point of the waveform (first 10 bits)
DPSK and delay)
- 2020-12-14 08:19:14下载
- 积分:1
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tcdg
Encryption has become a part and parcel of our lives and we have accepted the fact that data is going to encrypted and decrypted at various stages. However, there is not a single encryption algorithm followed everywhere. There are a number of algorithms existing, and I feel there is a need to understand how they work. So this text explains a number of popular encryption algorithms and makes you look at them as mathematical formulas.
- 2014-01-29 15:57:35下载
- 积分:1
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FPGA向SRAM中写入数据,VHDL编程
FPGA向SRAM中写入数据,VHDL编程-FPGA to the SRAM write data, VHDL programming
- 2023-05-04 17:45:03下载
- 积分:1