-
chess
在N*N的棋盘上(1<=N<=10)填入1,2,...N*N共N*N个数,使得任意两个相邻的数之和为素数. (In the N* N chessboard (1 < = N < = 10) filled 1,2, ... N* N total number of N* N so that any two adjacent numbers and prime numbers.)
- 2009-06-01 11:21:39下载
- 积分:1
-
Josephus(data_struct)
数据结构中基于约瑟夫环问题,用C++方式实现的。。。。。(Data structure based on Josephus problem with C++ a manner. . . . .)
- 2013-11-17 11:30:24下载
- 积分:1
-
stack
数据结构 堆栈 实现了以下功能:
cout<<"----------------主菜单---------------"<<endl
<<"* 1.建立 *"<<endl
<<"* 2.输出 *"<<endl
<<"* 3.判断栈是否为空 *"<<endl
<<"* 4.栈的长度 *"<<endl
<<"* 5.输出栈顶元素 *"<<endl
<<"* 6.进栈 *"<<endl
<<"* 7.出栈 *"<<endl
<<"* 8.遍历 *"<<endl
<<"* 9.数制转换 *"<<endl
<<"* 10.清空 *"<<endl
<<"* 11.销毁 *"<<endl
<<"* 12.退出 *"<<endl
<<"--------------------------------------"<<endl<<endl (data structure stack)
- 2013-11-01 11:05:10下载
- 积分:1
-
Bigint
利用双向链表实现对两大整数的相加运算。
可以修改数组长度实现更大整数的相加(Realize the use of two-way linked list of integers the sum of the two operations. Can modify the array length to achieve a greater sum of integers)
- 2007-10-18 21:34:06下载
- 积分:1
-
Hash-table
本代码主要实现了哈希表的设计,完成了哈希函数的相关要求。(The code is designed to achieve a hash table, the completion of the relevant requirements of the hash function.)
- 2013-12-30 17:15:14下载
- 积分:1
-
astar
A*算法 1、将开始节点放入开放列表(开始节点的F和G值都视为0)
2、重复以下步骤:
在开放列表中查找具有最小F值的节点,并把查找到的节点作为当前节点
把当前节点从开放列表删除, 加入到封闭列表.
(A* algorithm 1, will begin to node placed in the and opening up list of (the began to node of the F and G values are regarded as 0) 2, repeat the the following steps: to Find a the has a the the smallest F value of the node in the the and opening up list of, and put Find a to the node as the current node current node is removed from the open list, added to the closed list.)
- 2013-04-04 11:06:42下载
- 积分:1
-
maze
说明: 由数字1和0组成迷宫,0代表可走路径,程序会用坐标的形式给出每一步的走法(Composed by a maze of numbers 1 and 0, 0 to go the path, the program will use the coordinates given in the form of moves at each step)
- 2011-03-27 20:57:47下载
- 积分:1
-
xunhuansaiqxf
算法课程设计 分治法解决循环赛日程表 源代码+word报告+答辩PPT(Curriculum design of divide and conquer algorithm to solve a round robin schedule report+ source code+ word reply PPT)
- 2010-05-26 23:51:17下载
- 积分:1
-
CR17_2014.05.19_list
数据结构线性表教学笔记,内容讲基础知识,没基础可以看看(Linear table data structure teaching notes, basic knowledge content says, no base can take a look)
- 2014-06-09 23:35:37下载
- 积分:1
-
linked
关于二叉树的一些相关代码,运用链表的形式,求二叉树的高度,结点个数以及叶节点个数(Some of the relevant code on the binary tree, using a linked list, find the height of a binary tree, the number of nodes, and the number of leaf nodes)
- 2013-02-03 11:10:07下载
- 积分:1