MOPSO算法代码

ANSYS官方用户自定义函数学习文档，可以用于被ANSYS FLUENT求解器动态加载以增强其标准功能的C语言程序。

matlab对光栅反射率光谱的仿真代码，程序运行后能显示图形。

本资源中包含CFAR算法的源代码、测试数据以及使用教程。本资源是在Matlab2017b中调试可用，教程中包含MinGW编译器的下载地址和安装方法和mex文件混编的步骤，非常的全面，供大家下载学习！

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The Verilog® Hardware Description Language (Verilog HDL) became an IEEE standard in 1995 as IEEEStd 1364-1995. It was designed to be simple, intuitive, and effective at multiple levels of abstraction in astandard textual format for a variety of design tools, including verification simulation, timiThe clear directive from the users for these three task forces was to start by solving some of the followingproblemsConsolidate existing IeeE Std 1364-1995Verilog generate statementMulti-dimensional arraysEnhanced Verilog file i/oRe-entrant tasksStandardize Verilog configurationsEnhance timing representationEnhance the vpi routinesAchievementsOver a period of four years the 1364 Verilog Standards Group(vsg) has produced five drafts of the lrmThe three task forces went through the EEe Std 1364-1995 lRM very thoroughly and in the process of consolidating the existing Lrm have been able to provide nearly three hundred clarifications and errata for theBehavioral, ASIC, and PLI sections. In addition, the vsg has also been able to agree on all the enhance-ments that were requested (including the ones stated above)Three new sections have been added. Clause 13, "Configuring the contents of a design, deals with configuration management and has been added to facilitate both the sharing of verilog designs between designersand/or design groups and the repeatability of the exact contents of a given simulation session Clause 15Timing checks, "has been broken out of Clause 17, "System tasks and functions, "and details more fullhow timing checks are used in specify blocks. Clause 16, "Backannotation using the Standard Delay Format(SDF), addresses using back annotation(IEEE Std 1497-1999)within IEEE Std 1364-2001Extreme care has been taken to enhance the vpi routines to handle all the enhancements in the behavioraland other areas of the lrm. minimum work has been done on the pli routines and most of the work hasbeen concentrated on the vpi routines. Some of the enhancements in the vpi are the save and restart simu-lation control, work area access, error handling, assign/deassign and support for array of instances, generateand file 1/0Work on this standard would not have been possible without funding from the cas society of the ieee andOpen verilog InternationalThe IEEE Std 1364-2001 Verilog standards Group organizationMany individuals from many different organizations participated directly or indirectly in the standardizationprocess. The main body of the Ieee Std 1364-2001 working group is located in the United States, with asubgroup in Japan (EIAJ/1364HDL)The members of the IEEE Std 1364-2001 working group had voting privileges and all motions had to beapproved by this group to be implemented the three task forces focused on their specific areas and theirrecommendations were eventually voted on by the Ieee Std 1364-2001 working group

利用STM32+DAC+TIM+DMA产生正弦波（亲测最高达到60KHz）测试平台为正点原子精英板F103ZeT6

【实例简介】自适应中值滤波 MATLAB程序 滤波效果很好 自适应中值滤波 滤波效果很好

历年计算机二级MS_Office真题及答案

2017最全华为机试题C/C++（含答案源码)，包含111道上机考试题，欢迎下载，觉得资源好请好评。分别将字符串中的字符转换成整型数字,进行计算后,再转换成字符类型存储起来数为其中和是输入,是的长度,是的长度。是输出4.删除子串,只要是原串中有相同的子串就删掉,不管有多少个,返回子串个数输出删除后的字符串删除子串5.约瑟夫环是一个数学的应用问题:已知n个人(以编号1,2,3..n分别表示)围坐在一张圆桌周围。从编号为k的人开始报数,数到m的那个人出列:他的下一个人又从1开始报数,数到m的那个人又出列;依此规律重复下去,直到圆桌周围的人仝部出列。6.比较一个数组的元素是否为回文数组比较两个数组,要求从数组最后一个元素廾始逐个元素冋前比较,如果2个数组长度不等,则只比较较短长度数组个数元素。请编程实现上述比较,并返回比较中发现的不相等元素的个数比如:数组{1,3,5}和数组77,21,1,3,5}按题述要求比较,不相等元素个数为0数组{1,3,5}和数组:77,21,1,3,5,7按题述要求比较,不相等元素个数为3要求实现函数int array compare(int len1, int array1[], int len2, int array2[l输入】 int len1:输入被比较数组1的元素个数;int array l[]:输入被比较数组1;int lcn2:输入被比较数组2的元素个数;int array2L]:输入被比较数组2【输出】无【返回】不相等元素的个数,类型为int小例1)02: int array1[ =11,3, 5, int len1=3, int array 2=77, 21, 1, 3, 51int e函数返回:02)输入: int array1[]=:1,3,5),int1en1=3, int array2={7,21,1,3,5,7int lend6函数返回:3约瑟大环变种:输入一个由随机数组成的数列(数列中每个数均是大于0的整数,长度已知),和初始计数值m。从数列首位置开始计数,计数到m后,将数列该位置数值替换计数值m,并将数列该位置数值出列,然后从下一位置从新开始计数,直到数列所有数值出列为止。如果计数到达数列尾段,则返回数列首位置继续计数。请编程实现上述计数过程,同时输出数值岀列的顺序比如:输入的随机数列为:3,1,2,4,初始计数值m-7,从数列首位置开始计数(数值3所在位置)第一轮计数出列数字为2,计数值更新m2,出列后数列为3,1,4,从数值4所在位置从新开始计数第二轮计数出列数字为3,计数值更新m3,出列后数列为1,4,从数值1所在位置开始计数第三轮计数出列数字为1,计数值更新m=1,出列后数列为4,从数值4所在位置开始计数最后一轮计数出列数字为4,计数过程完成。输出数值出列顺序为:2,3,1,4。要求实现函数id array iterate(int len, int input array [, int m, int output array [)输入】 int len:输入数列的长度;int Intput array[]:输入的初始数列intm:初始计数值【输出】 int output array[]:输出的数值出列顺序【返回】无示例输入: int input array[13,1,2,4}, int lcn4输出: output array[]2,3,1,4手机弓码合法性:问题描述:我国大陆运营商的手机号码标准格式为:国家码+手机号何,例如:8613912345678。特点如下:、长度13位2、以86的国家码打头3、手机号码的每一位都是数字。请实现手机号码合法性判断的函数要求1)如果手机号码合法,返回02)如果手机号码长度不合法,返回13)如果于机号码中包含非数字的字符,返回24)如果于机号码不是以86打头的,返回3:【注】除成功的情况外,以上其他合法性判断的优先级依次降低。也就是说,如果判断出长度不合法,直接返回1即可,不需要再做其他合法性判断。要求实现函数int verifyMsisdn (chark inMsisdn)【输入】char* inmsisdn,表示输入的手机号码字符串。【输出】无【返回】判断的结果,类型为int示例输入: inMsisdn=“869123456789“输出:无返回:1输入: msisdn=“88139123456789输出:无输入: inMsisdn=“86139123456789“输出:无返简单的四则运算问题描述:输入一个只包含个位数字的简单四则运算表达式字符串,计算该表达式的值注:1、表达式只含,,(,),四则运算符2、表达式数值只包含个位整数(0-9),且不会出现0作为除数的情况3、要考虑加减乘除按通常四则运算规定的计算优先级4、除法用整数除法,即仅保留除法运算结果的整数部分。比如8/3=2。输入表达式保证无0作为除数情况发生5、输入字符串一定是符合题意合法的表达式,其屮只包括数字字符和四则运算符字符,除此之外不含其它任何字符,不会出现计算溢出情况要求实现函数:int calculatc(int lcn, char *cxpStr输入】 int cn:字符串长度;char* cxpStr:表达式字符串【输出】无【返回】计算结果示例1)输入:char* expstr“1+4*5-8/3函数返回:192)输入:char* expStr=“8/3*3”函数返回:6

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