Dijkstra

此代码为折半查找算法，适用于有序表，欢迎各位下载(This code is the binary search algorithm for ordered lists )

通过c语言数组算法解决josephus问题，m个人围成一圈，从第一个小孩开始顺时针方向每数到第n个小孩时这个小孩离开，最后剩下的小孩是胜利者。求第几个小孩为胜利者(C language array algorithm to solve the Josephus problem, m individual circle, from the first child began to count clockwise every n children, the child left, and finally the remaining child is the winner. A few kids for victory)

说明：  在给定的字母中，用c++来实现字母的排序(In a given letter, the use of c++ to implement the letter of the sort)

穷举算法，VC中的经典程序之一，适合初学者，(Brute-force algorithm, the the of the classic procedures in in the the VC, suitable for beginners)

这是一个堆排序的算法源程序，算法被单独写成一个函数，希望对大家有用(This is a heap sort algorithm source code, algorithms are written as a separate function, we hope to be useful)

魔方问题 数据结构 使用c++ 经典问题(Cube problem Data Structure Using c++ Classic problem)

建立链表的算法： 新节点链入表尾建立链表： 动态分配第一个节点变量； 用指针head 妥善保存链表第一个节点的地址值； 依次动态分配一个新节点变量； 将上一个节点的指针域指向新生成的节点； 循环3),4)步骤，直到所有节点均连入链表； 将最后一个节点的指针域赋值为0； (Establish the list of algorithms: The new node links footer build list: Dynamic allocation of the first node variable Keep the list head pointer of the first node address value In order to dynamically allocate a new node variable The domain of a node pointer to the new generation of nodes Cycle 3), 4) step, until all nodes are connected to the chain Pointer field will last node assigned to 0 )

采用邻接矩阵实现有向网的存储，建立有向网，并实现单源最短路径算法。(The realization of the use of adjacency matrix to the network storage, the establishment of the network, and to achieve single-source shortest path algorithm.)

数据结构 堆栈 实现了以下功能： cout<<"----------------主菜单---------------"<<endl <<"* 1.建立 *"<<endl <<"* 2.输出 *"<<endl <<"* 3.判断栈是否为空 *"<<endl <<"* 4.栈的长度 *"<<endl <<"* 5.输出栈顶元素 *"<<endl <<"* 6.进栈 *"<<endl <<"* 7.出栈 *"<<endl <<"* 8.遍历 *"<<endl <<"* 9.数制转换 *"<<endl <<"* 10.清空 *"<<endl <<"* 11.销毁 *"<<endl <<"* 12.退出 *"<<endl <<"--------------------------------------"<<endl<<endl (data structure stack)

迷宫问题c源代码，大小为8*8的迷宫。主函数中输入开始位置和结束位置的坐标，输出所有可能的路径(Maze c source code, size 8* 8 of the maze. Enter the start the main function of the coordinates of the position and end position, the output of all possible paths)