AFMR

应用matlab/dsp builder可以对多种类型的电子线路模块或系统进行建模、分析和硬件实现，本文档给出了一些使用模块的设计实例，让大家更好的学习。(Application matlab/dsp builder can be various types of electronic circuit modules or systems modeling, analysis and hardware implementation, this document gives some examples using the design module, so that we better learning.)

Simple mouse control using motion detection with matlab. It s not perfect, just an outline, needs improvements.

可实现微电网中分布式电源的下垂控制，采用三环控制策略，节点既可作为V/f结点，也可作为PQ结点(It can achieve distributed generation droop control in Microgrid, which uses three-loop control strategy. The node can be used as V/f node, the node can also be used as PQ node)

说明：  calculating using jacobi on matlab numeric

说明：  一个自适应控制方面的Simulink程序，主要解决无模型自适应（MFA）控制的问题(Adaptive control of a Simulink procedures, mainly to solve the model-free adaptive (MFA) control)

验证研所感知理论，最基本的算法实现！很不错的学习程序(compress sensing program)

maze solved with q learning

产生右图所示图像f1(m,n)，其中图像大小为256×256，中间亮条为128 ×32，暗处=0，亮处=100。对其进行FFT： ① 同屏显示原图f1(m,n)和FFT(f1)的幅度谱图； ② 若令f2(m,n)=（-1）m+n f1(m,n)，重复以上过程，比较二者幅度 谱的异同，简述理由； ③ 若将f2(m,n)顺时针旋转90 度得到f3(m,n)，试显示FFT(f3)的幅 度谱，并与FFT(f2)的幅度谱进行比较； ④ 若将f1(m,n) 顺时针旋转90 度得到f4(m,n)，令f5(m,n)=f1(m,n)+f4(m,n)，试显 示FFT(f5)的幅度谱，并指出其与FFT(f1)和FFT(f4)的关系； ⑤ 若令f6(m,n)=f2(m,n)+f3(m,n)，试显示FFT(f6)的幅度谱，并指出其与FFT(f2)和 FFT(f3)的关系，比较FFT(f6)和FFT(f5)的幅度谱。(Generating an image f1 (m, n) shown in the figure, wherein the image size is 256 256, the intermediate light bar 128 32 0 = dark, bright Department 100. Its FFT: ① screen display picture f1 (m, n) and the FFT (f1) of the amplitude spectrum ② If so f2 (m, n) = (-1) m+n f1 (m, n), repeat The above process, comparing the amplitude spectrum of the similarities and differences between the two, brief reasons ③ If f2 (m, n) 90 degrees clockwise to get f3 (m, n), try to display FFT (f3) the amplitude spectrum and with the FFT (f2) comparing the amplitude spectrum ④ If f1 (m, n) obtained by 90 degrees clockwise f4 (m, n), so f5 (m, n) = f1 (m, n)+f4 (m, n ), try to display FFT (f5) amplitude spectrum, and pointed out its relationship with the FFT (f1) and FFT (f4) of ⑤ If so f6 (m, n) = f2 (m, n)+f3 (m, n) and try to display the FFT (f6) amplitude spectrum, and pointed out its relationship with the FFT (f2) and FFT (f3), comparing FFT (f6) and FFT (f5) amplitude spectrum.)

说明：  IEEE 14 bus 的matlab仿真模型(Matlab simulation model of IEEE 14 bus)

一个基于MATLAB的径向基的神经网络源程序(a MATLAB-based RBF neural network source)