Haffman

这是birch C语言的源代码。里面有详细的代码注释方便学习birch算法(birch c)

计算机博弈大赛不围棋的代码 个人所写，可以用来参考( U8BA1 u7B97 u673A u535A u5F08 u5927 u8D5B u4E0D u56F4 u68CB u7684 u4EE3 u7801 u4E2A u4EBA u6240 u5199 uFF0C u53EF u4EE5 u7528 u6765 u53C2 u8003)

单循环链表，用C++实现 提供入队，出队，判断空等方法(Single cycle linked list, with C++ into the team, the team judge waited in vain for methods)

数据结构中数据的排序示例,包括堆排序、快速排序等(Data structure to sort the data sample, including the heap sort, quick sort, etc.)

说明：  拓扑排序 　 对一个 有向无环图 G进行拓扑排序，是将G中所有顶点排成一个线性序列，使得图中任 意一对顶点u和v，若u，v ∈E，则u在线性序列中出现在v之前。 　 通常，这样的线性序列称为满足拓扑次序的序列，简称 拓扑序列 。 注意： 　 ①若将图中顶点按拓扑次序排成一行，则图中所有的有向边均是从左指向右的。 　 ②若图中存在有向环，则不可能使顶点满足拓扑次序。 　 ③一个DAG的拓扑序列通常表示某种方案切实可行。 (Topological sort In a directed acyclic graph G topological sort, is all vertices will G formed a linear sequence, make diagram post Meaning a pair of vertex u and v, if u, v ∈ E, then u in linear sequence in which they appear in v before. Usually, such linear sequence sequence of topological order called meet, abbreviation topology sequence. Note: (1) if the diagram according to the topology order line vertices, then figure all from left to right edge are pointing. (2) if the figure to exist in the ring, is impossible to have the vertex meet topological sequence. (3) a DAG topological sequence usually expressed some scheme is feasible. )

说明：  由数字1和0组成迷宫，0代表可走路径，程序会用坐标的形式给出每一步的走法(Composed by a maze of numbers 1 and 0, 0 to go the path, the program will use the coordinates given in the form of moves at each step)

说明：  数据结构基本算法实现。包括栈、二叉树基本运算实现，同时包含整数计算器的完整实现。(The basic algorithm data structure. Including implementation of stack, binary tree basic operations, and a complete implementation of an integer calculator.)

数据结构课上老师布置的5个小项目的源代码，分别是汽车过河，一元多项式，迷宫，日历，BFS_DFS(failed to translate)

说明：  链表逆转,实现单链表的逆转程序，数据结构(List Inverse)

/*快速排序：以待排序元素中的第一个元素作为基准将带排序的元素分为三组 *大于基准元素为一组置于基准值的右边，小于基准值的元素为一组置于基准值的左边， *基准值为一组，这样就找到了基准元素的位置就确定了 *如此递归调用。直到每一组的low==high，即实现了排序的要求。 */ (/* Rapid Sort: the first element to be sorted in the element as a basis with with sorting the elements are divided into three groups* is greater than the reference element of a group is placed on the right side of the reference value, smaller than the reference value elements for a group of placed on the left side of the reference value,* reference value, a group, so that the location of the reference element is found it is determined* so recursive call. Until each group of low == high to achieve the requirements of the sort.* /)