jiajianfa

说明：  进程死锁.资源分配图的绘制 建立所需数据结构；  使用题目21存成的资源分配图的文件作为输入；  编写资源分配图化简算法；  每化简一步，在屏幕上显示化简的当前结果；  最后给出结论，是否死锁，如思索给出死锁的进程及资源； (Process deadlock. Resource allocation mapping  establish the required data structures  Use title 21 deposit into resource allocation graph file as input  writing resource allocation map simplification algorithm  Each simplification step, on-screen display simplification of the current result  Finally, the conclusion of a deadlock, deadlock is given as thinking processes and resources )

基于MFC平台，实现多功能计算器，可求解复杂表达式，主要实现为数据结构中链表和数组，对于要熟悉链表和数组的初学者有很帮助。(Based on the MFC platform, to achieve multi-function calculator, can solve complex expressions, the main realization of the data structure for the list and array, to be familiar with the list and the array of beginners helpful.)

图的遍历的实现，文字界面，包含深度遍历和广度遍历两种情况~~(Graph traversal implementation, the text interface, including the depth and breadth traversal traverse both cases ~ ~)

数据结构，关键路径问题，设计并实现关键路径的一种应用，采用图的算法(Data structure, critical path problem, using graph algorithm)

插入排序与合并排序的算法比较，比较两种算法的优劣(Comparison of insertion sort and merge)

实现超市中排队购物用时最短，是计算机算法设计与分析中的一道题。自己写的程序，原创！(Achieve queued supermarket shopping with the shortest, is a question in the design and analysis of computer algorithms. Write their own procedures, original!)

/*快速排序：以待排序元素中的第一个元素作为基准将带排序的元素分为三组 *大于基准元素为一组置于基准值的右边，小于基准值的元素为一组置于基准值的左边， *基准值为一组，这样就找到了基准元素的位置就确定了 *如此递归调用。直到每一组的low==high，即实现了排序的要求。 */ (/* Rapid Sort: the first element to be sorted in the element as a basis with with sorting the elements are divided into three groups* is greater than the reference element of a group is placed on the right side of the reference value, smaller than the reference value elements for a group of placed on the left side of the reference value,* reference value, a group, so that the location of the reference element is found it is determined* so recursive call. Until each group of low == high to achieve the requirements of the sort.* /)

迷宫问题c源代码，大小为8*8的迷宫。主函数中输入开始位置和结束位置的坐标，输出所有可能的路径(Maze c source code, size 8* 8 of the maze. Enter the start the main function of the coordinates of the position and end position, the output of all possible paths)

poj 实现堆结构的源代码。。。话说其实没什么实际功能好么(poj achieve heap structure of the source code. . . In fact, the actual function of saying okay nothing)

说明：  ACM及各类基本算法模板，包括数据结构，计算几何，字符串，图论，数学，高精度等许多常用模板(ACM basic algorithm and various templates, including data structures, computational geometry, string, graph theory, mathematics, high-precision, and many other commonly used templates)