mifeng

迷宫求解一般采用“穷举法”，逐一沿顺时针方向查找相邻块（一共四块－东(右)、南(下)，西(左)、北(上)）是否可通，即该相邻块既是通道块，且不在当前路径上。用一个栈来记录已走过的路径栈是限定仅在表尾(top)进行插入或删除操作的线性表。(Maze solving generally use the " exhaustive" one by one to find adjacent blocks in a clockwise direction (a total of four- East (right), South (down), West (left), North (on)) whether to pass, that the both channel blocks adjacent blocks, and not in the current path. Use a stack to record the path traversed stack is limited only in the tail (top) to insert or delete a linear form.)

数据结构基础内容，两栈共享空间，参考《大话数据结构》(Structural basis of data content, two stacks shared space, refer to Westward data structure )

算法分析与设计——大整数乘法。 计算两个超出机器数表示范围的整数的乘积。(Algorithm Analysis and Design- large integer multiplication. Calculating the number of two machines that go beyond the scope of the product of an integer.)

大一c语言实验的所有源码以及实验报告报告(All source code and report experimental freshman c language)

迷宫问题c源代码，大小为8*8的迷宫。主函数中输入开始位置和结束位置的坐标，输出所有可能的路径(Maze c source code, size 8* 8 of the maze. Enter the start the main function of the coordinates of the position and end position, the output of all possible paths)

用分治算法（O(nlogn)复杂度）实现寻找n个点中最邻近点对,输出为最邻近距离的平方(Looking for n points nearest point, the output of the nearest neighbor distance squared using the divide-and-conquer algorithm (O (nlogn) complexity))

建立链表的算法： 新节点链入表尾建立链表： 动态分配第一个节点变量； 用指针head 妥善保存链表第一个节点的地址值； 依次动态分配一个新节点变量； 将上一个节点的指针域指向新生成的节点； 循环3),4)步骤，直到所有节点均连入链表； 将最后一个节点的指针域赋值为0； (Establish the list of algorithms: The new node links footer build list: Dynamic allocation of the first node variable Keep the list head pointer of the first node address value In order to dynamically allocate a new node variable The domain of a node pointer to the new generation of nodes Cycle 3), 4) step, until all nodes are connected to the chain Pointer field will last node assigned to 0 )

八皇后算法，用的是最简单的穷举法，在VC++6.0上编写的。(Eight Queens algorithm, using the simplest method of exhaustion, in VC++6.0 written on.)

输入N个点的坐标，判断这N个点能否构成一个凸多边形。(Enter the coordinates of N points, to determine whether the N points form a convex polygon.)

该ppt包含了栈和队列的数据结构及基本操作，同时还有栈的举例(This ppt contains the stack and queue data structure and basic operation, as well as examples of the stack)