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Timer
这是一个定时器程序。适合于单片机初学者……(This is a timer program. Suitable for beginners ... ... MCU)
- 2009-12-10 18:57:58下载
- 积分:1
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angle-time
用于计算同步电机发生三相短路故障时,功角随时间的变化关系。(For the calculation of the three-phase short circuit fault occurs synchronous motors, power angle changes with time.)
- 2015-04-14 13:23:34下载
- 积分:1
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2.4TFT_C51_Pictures_showed_test_procedures
2.4寸 TFT液晶屏在C51单片机上的刷屏测试程序(2.4-inch TFT LCD screen on a single chip in the C51 test procedure Shuabing)
- 2010-07-20 18:41:05下载
- 积分:1
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V2[1][1]
载波模块,现成的PCB板。。。。。。。。。(。。。。。。。。。。。。。。。。。。。。。。)
- 2010-01-21 20:35:15下载
- 积分:1
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ADCzhuanhuan
单片微型计算机简称单片机,是典型的嵌入式微控制器(Microcontroller Unit),
单片机芯片
常用英文字母的缩写MCU表示单片机,单片机又称单片微控制器,它不是完成某一个逻辑功能的芯片,而是把一个计算机系统集成到一个芯片上。(Microcontroller chip microcomputer referred to, is a typical embedded microcontroller (Microcontroller Unit),
Single chip
Commonly used letters of the abbreviation indicates MCU microcontroller, microcontroller, also known as single-chip microcontroller, it is not complete a certain logic functions of the chip, but to a computer system integrated into a single chip.)
- 2013-09-10 20:10:24下载
- 积分:1
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ses
有限差分波动方程不加边界条件二阶正演时间切片程序。(Finite difference wave equation without boundary conditions of second-order forward time-slicing procedure.)
- 2009-12-11 16:54:20下载
- 积分:1
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iPhone-QQ-HeadPic
Central Empire dedicated source
- 2013-07-22 09:12:04下载
- 积分:1
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xiaocheyanluzou
小车沿着黑带前进,这事往年一个竞赛题目的程序,对大家有帮助。(The car along the black belt, it past a contest questions purpose program, are helpful to you.
)
- 2013-08-19 11:38:13下载
- 积分:1
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适用于AVR系列单片机的几种C语言比较
说明: 使用于AVR单片机的几种C语言,大家可以参考一下,以便以后在AVR的程序编写中提高自己(used in the AVR several C language, we can make reference to the AVR after the procedure to improve their writing)
- 2005-12-17 12:40:39下载
- 积分:1
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numeric-trapezium
一个数字梯形,选择k条路线,每条路线从第一层的某个数开始,每次进入下一层到达左下或者右下的数字,直到最后一层为止。每条路线不能经过相同的路径,但是可以经过相同的数字节点。 输出一个整数,表示能得到的最大的k条路径经过的数字之和(A digital ladder, the K route, each route the first layer of a number, each time to enter the next layer to reach the left or right next to the number, until the final layer. Each route can not pass through the same path, but can pass through the same number of nodes. Output an integer representing the sum of the number of the largest K paths that can be obtained)
- 2020-11-19 11:09:38下载
- 积分:1