Work3.5

纯C语言写的小型通用数据库，一个C数据结构组科技小组的作品，附有开发思路PPT，这可是一个宝贵的资源哦，更底层的东西，运行于DOS提示符，可以新建数据库等操作。C的编程高手们值得参考一下。 (Pure C language to write a small general-purpose database, a data structure C Group Technology Group works to develop ideas with PPT, this is a valuable resource Oh, and the bottom of things, running on the DOS prompt, you can operate a new database. C programming masters worthy of reference.)

无环连通图G=(V, E)亦称为自由树T，其直径是树中所有顶点之间最短路径的最大值，设计一个算法求T的直径(Acyclic connected graph G = (V, E) is also known as free tree T, whose diameter is the tree of shortest paths between all vertices maximum design an algorithm for the diameter of T)

二叉树的C++实现，成员可以自己调整，实现了各种修剪此树的方法：初始化，增加节点，删去节点，复制树，读取节点，遍历树(Binary tree in C++, members can make their own adjustments to achieve a variety of pruning this tree methods: initialize, add nodes, delete nodes, copy the tree, read the node, traverse the tree)

COM中使用SAFEARRAY数组例程，代码中给了两种数组的用法，一种是字符串数组，另一种是自定义数据结构数组。 (use COM SAFEARRAY array routines, a code for the use of two arrays, a string array, and the other is from the definition of array data structure.)

C语言实现井字棋博弈的过程，采用极大极小算法。(The C language game of tic-tac-toe chess, using the minimax algorithm.)

数据结构 堆栈 实现了以下功能： cout<<"----------------主菜单---------------"<<endl <<"* 1.建立 *"<<endl <<"* 2.输出 *"<<endl <<"* 3.判断栈是否为空 *"<<endl <<"* 4.栈的长度 *"<<endl <<"* 5.输出栈顶元素 *"<<endl <<"* 6.进栈 *"<<endl <<"* 7.出栈 *"<<endl <<"* 8.遍历 *"<<endl <<"* 9.数制转换 *"<<endl <<"* 10.清空 *"<<endl <<"* 11.销毁 *"<<endl <<"* 12.退出 *"<<endl <<"--------------------------------------"<<endl<<endl (data structure stack)

本书是《程序员面试宝典》的第三版，在保留第二版的数据结构、面向对象、程序设计等主干的基础上，使用各大IT公司及相关企业最新面试题替换和补充原内容，以反映自第一版以来近几年时间所发生的变化。 　　欧立奇、刘洋、段韬编著的《程序员面试宝典》取材于各大公司面试真题(笔试、口试、电话面试、英语面试，以及逻辑测试和智商测试)，详细分析了应聘程序员(含网络、测试等)职位的常见考点。本书不仅对传统的C系语言考点做了详尽解说，还根据外企出题最新特点，新增加了对友元、Static、图形/音频、树、栈、ERP等问题的深入讲解。最后本书着力讲述了如何进行英语面试和电话面试，并对求职中签约、毁约的注意事项及群体面试进行了解析。本书的面试题除了有详细解析和答案外，对相关知识点还有扩展说明。真正做到了由点成线，举一反三，对读者从求职就业到提升计算机专业知识都有显著帮助。 　　《程序员面试宝典》适合计算机相关专业应届毕业生阅读，也适合作为正在应聘软件行业的相关就业人员和计算机爱好者的参考书。(This book is the" canon" in the third edition, retained in the second version of the data structure, object-oriented program design, main basis, the use of each big IT companies and related enterprises to the latest interview questions substitution and supplement the original content, in order to reflect the since its first edition in recent years since time changes. Ou Liqi, Liu Yang, Duan Tao," canon" drawn from major companies interview questions ( written examination, interview, telephone interview, interview, and logical test and IQ test ), a detailed analysis of the application programmer (including network, testing ) positions of the common points. This book not only to the traditional C language test done a detailed explanation, according to the new characteristics of the new foreign title, added to the friend, Static, graphics/audio, tree, stack, ERP issues in depth explanation. The last book on described how the English interview and telephone interview, and the job of signin)

中国大学MOOC-陈越、何钦铭-数据结构 解题报告—06-3 六度空间 (Chinese University MOOC- Chen Yue, He Qinming- data structure Solving report of the problem- 06-3 Six degrees space)

八皇后问题，用vc编写了一个可以解决八皇后问题的程序，实现了递归调用。(The eight queens problem, using vc write a means of solving the eight queens problem program to achieve the recursive calls.)

读取数据，统计所得到的文件中每个字母的权值，创建哈夫曼树，哈夫曼编码。哈夫曼解码，解码后内容写入到指定的文件。 读取数据里面的内容是由英文单词组成。读取文件的时候传入文件存放的路径、读取方式以及读出以后存放的数组，最终可以得到一个存放目标文件内容的数组。 将得到的数组进行字母权值的统计，统计每个字母出现的次数，次数即为每个字母的权值。 将得到的字符数组与权值数组作为创建哈夫曼树的依据，哈夫曼树根据每个字母权值的大小来创建，每个节点，包括权值、父节点、左子、右子和字母本身。 根据哈夫曼树进行编码。形成目标文件的哈夫曼编码，将此编码返回。 根据哈夫曼树得到的数组即为解码数组，解码数组作为解码的结果返回。 写入输出文件，将解码得到的数组、文件的完整路径以及文件的写方式作为参数传入，将数组写入到相应的文件中。 (Read the data, statistical documents obtained weights for each letter, create a Huffman tree, Huffman coding. Huffman decoding, the decoded contents are written to the specified file. Read the content inside is composed of English words. When the incoming file to read the file storage path, read mode and read out after storage array that can eventually get a storage target file contents of the array. The resulting array of letter weights statistics, statistical number of occurrences of each letter, the number is the weight of each letter. The resulting character array with the weights array as the basis for creating Huffman tree, Huffman tree based on the size of the weights of each letter to create, for each node, including weights, parent, left child, right child, and letter itself. According to Huffman coding. The formation of the target file Huffman coding, this code returns. According to Huffman decoding the resulting array is an array, the decoder decodes the result is retur)