matlabxiabo

C Code example with EII

矩阵相乘，基于CUDA用并行算法实现矩阵的乘法(matrix muliplication with parallel algorithm implication matrix muliplication base on CUDA )

位置感知应用程序市场 位置估算技术 其它S60 平台运行时中的位置API 使您的应用程序感知位置时需要考虑的因素 协助测试的开发工具。(Location-aware applications market position estimation techniques other S60 platform run-time the position of the API to your application-aware location factors to be considered to help test the development tools.)

效率极高的基于delaunay三角网格剖分程序，只是没有图形输出，可以只将生成文件直接导入matlab中。(Based on highly efficient delaunay triangular mesh generation process, but there is no graphics output, you can only generate documents in directly into matlab.)

提供了通用的asn1编解码动态库,实现BER和PER方式的asn1编解码。并提供使用实例和说明。(provides a common asn1 DLL codecs achieve BER and PER approach asn1 codecs. And to provide the use of examples and illustrations.)

to make dll using matlab

自己编写的迭代小程序，小程序，没问题额的啊(I have written a small program iteration, a small program, the amount of, ah no problem)

两个设备形成对射，当有人通过时，一台设备发出指令，控制别的设备。(Two devices formed on the radio, when someone passed a device to issue commands to control other devices.)

根据2FSK调制器与解调器的组成原理，设计出整个2FSK传输系统的实现方案与电路(Based on composition theory 2FSK modulator and demodulator, the entire design implementation and circuit transmission system 2FSK)

递归法求解整数划分。 整数划分，是指把一个正整数n写成如下形式： n=m1+m2+…+mi （其中mi为正整数，并且1 <= mi <= n），则{m1,m2,...,mi}为n的一个划分。 如果{m1,m2,...,mi}中的最大值不超过m，即max(m1,m2,...,mi)<=m，则称它属于n的一个m划分。这里我们记n的m划分的个数为f(n,m) (Recursive method integer division. Integer division, refers to a positive integer n written as follows: n = m1+m2+ ...+mi (where mi is a positive integer, and 1 < = mi < = n), then {m1, m2, ..., mi} is a division of n. If {m1, m2, ..., mi} does not exceed the maximum value of m, i.e., max (m1, m2, ..., mi) < = m, m n is said that it belongs to a division. Where m is the number of division n our mind is f (n, m) )