登录
首页 » Visual C++ » charu

charu

于 2014-11-15 发布 文件大小:1158KB
0 270
下载积分: 1 下载次数: 3

代码说明:

  请输入非递减的有序序列,输入-1结束,再输入一个数字,插入其中,按照从小到大的顺序进行排列,完成这个程序(Please enter a non-decreasing ordered sequence, enter-1 end, and then enter a number, into which, in ascending order of arrangement, complete this program)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • wuziqi
    说明:  声明:本程序仅交流用,所以调试时用两颗棋子就可以赢(Disclaimer: This procedure only exchange with, so debugging can win with two pieces)
    2010-05-01 17:34:45下载
    积分:1
  • FDTD2D
    一个FDTD二维的经典程序,非常不错,适合初学者使用。(A classic two-dimensional FDTD program, very good, suitable for beginners.)
    2011-01-23 11:29:28下载
    积分:1
  • K-mean
    最近邻分类器是一个用来聚类的算法,可以用来对iris数据进行聚类(k-means is a neanest alogorim)
    2011-06-28 12:14:32下载
    积分:1
  • weixingdingwei
    作者在学习《航天系统》时,在c++6.0环境中实现的卫星定位的算法程序。包括通过轨道根数求卫星状态参数的算法和通过卫星状态参数反求卫星星历的算法。(Author of the study "space system" is in c++6.0 environment to achieve the satellite positioning algorithm. Including through the orbital parameters of the algorithm for the satellite status and Reverse status parameters via satellite satellite ephemeris algorithms.)
    2013-09-25 19:42:10下载
    积分:1
  • basic
    matlab中许许多多的基础图像处理方法,最适合初学者使用,希望采纳哦(matlab image processing method in the base of many of the most suitable for beginners to use, hope to adopt oh)
    2015-03-18 14:51:43下载
    积分:1
  • sceneComplete
    Scene completion.This is a toy implementation of Scene Completion Using Millions of Photographs for 6.870 Object Recognition and Scene Understanding.(This implementation uses a of 54,000 256x256 images the Oliva lab for which we already have gist-based nearest neighbors data. )
    2015-04-20 10:49:28下载
    积分:1
  • NumberToTextFrench
    Return a number in to french
    2015-01-02 22:43:18下载
    积分:1
  • ZH
    说明:  光学夫朗和费衍射现象模拟Matlab源代码 (Optical phenomenon of Fraunhofer diffraction simulation Matlab source code)
    2009-08-06 08:50:52下载
    积分:1
  • surshrHEDA
    基于直方图的分布估计算法matlab源程序,测试函数选用的是30维函数(for h=1:m for j=1:((x2-x1)/binswidth) if (x(h)>=x1+(j-1)*binswidth)&(x(h)<x1+j*binswidth) H(j)=H(j)+1 end end end [wid,len]=size(H) H=H/(wid*len) objvalue=sort(objvalue, descend ) for j=1:((x2-x1)/binswidth))
    2013-03-15 10:44:15下载
    积分:1
  • romberg
    用龙贝格法求定积分,此例的变量数为三,但整体思路是没错的。(With Romberg method for the definite integral, the number of variables in this case is three, but the overall idea is correct.)
    2011-12-21 10:12:03下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载