Maze

哈夫曼树可以使读者快速方便的查找所需文件(Huffman tree allows readers to quickly and easily find the file)

参加数学建模的同学很可能会遇到这套题。本程序采用链表进行编写，很方便地解决了小白鼠问题。(Mathematical modeling of the students participating are likely to encounter this question, the program uses the list to solve the problem of mice, very convenient.)

说明：  用从c＋＋写的floyd最短路径算法，可以求邻接矩阵任意两点的最短路径。(from using c++ to write the Floyd shortest path algorithm, can help adjacency matrix arbitrary 2:00 Shortest Path.)

给定n种物品和一背包。物品i的重量是wi>0,价值为vi>0,背包的容量为c。选择装入背包的物品，使得装入背包中物品的总价值最大。(Given n kinds of goods and a backpack. Weight of the item i is wi> 0, the value of vi> 0, knapsack capacity c. Select the items into the backpack, so into the backpack of items in the total value of the maximum.)

B-树的创建、插入、删除等一系列操作！(B-tree creation, insert, delete a series of manipulations!)

学数据结构自己总结的东西，希望对大家有所帮助。(Learn data structure sum things up, we want to help.)

建立链表的算法： 新节点链入表尾建立链表： 动态分配第一个节点变量； 用指针head 妥善保存链表第一个节点的地址值； 依次动态分配一个新节点变量； 将上一个节点的指针域指向新生成的节点； 循环3),4)步骤，直到所有节点均连入链表； 将最后一个节点的指针域赋值为0； (Establish the list of algorithms: The new node links footer build list: Dynamic allocation of the first node variable Keep the list head pointer of the first node address value In order to dynamically allocate a new node variable The domain of a node pointer to the new generation of nodes Cycle 3), 4) step, until all nodes are connected to the chain Pointer field will last node assigned to 0 )

使用全排列实现hash，看看吧相信对大家会有些帮助的(Full array hash)

约瑟夫问题，用数据结构的循环链表实现约瑟夫问题的解答(Joseph problems，30 people in a circle, and inspires us with a circular chain to said. Can use structure array to make a cycle chain. The structure has two members, one for pointing down a pointer to a circular chain )

以一个m*n的长方阵表示迷宫，0和1分别表示迷宫中的通路和障碍。设计一个程序，对任意设定的迷宫，求出一条从入口到出口的通路，或得出没有 通路的结论 (To an m* n the long square maze, 0 and 1, respectively maze of paths and obstacles. Design a program, for any set of the maze, find a path from the inlet to the outlet, or the conclusions drawn without passage)