fibonacci-heap

用从语言实现飞机订票系统。程序中用到了数据结构中的队列和栈。(From the language used airline reservation system. Process the data structure used in the queue and stack.)

开括号和比括号的匹配，数据结构内容，很不错(More than brackets and brackets to open the match, the contents of data structure)

数据结构中图的存储结构的建立与搜索 建立图的二种存储结构 在不同的结构上实现遍历 (Data structure diagram of the storage structure of the establishment of the search to establish two kinds of graph storage structure in the different structures to achieve through)

数据结构 堆栈 实现了以下功能： cout<<"----------------主菜单---------------"<<endl <<"* 1.建立 *"<<endl <<"* 2.输出 *"<<endl <<"* 3.判断栈是否为空 *"<<endl <<"* 4.栈的长度 *"<<endl <<"* 5.输出栈顶元素 *"<<endl <<"* 6.进栈 *"<<endl <<"* 7.出栈 *"<<endl <<"* 8.遍历 *"<<endl <<"* 9.数制转换 *"<<endl <<"* 10.清空 *"<<endl <<"* 11.销毁 *"<<endl <<"* 12.退出 *"<<endl <<"--------------------------------------"<<endl<<endl (data structure stack)

简单的一个链栈.即用链表实现的一个栈。可以做简单的插入、删除、查找等操作(this is a simple C++ program )

说明：  读取股票数据文件,C++源程序，非常好用。是学生做毕业设计的源料(Read the Stock Data File)

实现对二叉树的操作：建树、遍历、求层高、叶子数和结点数等(binary tree)

讲述数据机构的图论部分和程序设计的关系，适合学习算法的同学学习阅读，很不错的一本书。(Graph theory algorithm and programming)

说明：  拓扑排序 　 对一个 有向无环图 G进行拓扑排序，是将G中所有顶点排成一个线性序列，使得图中任 意一对顶点u和v，若u，v ∈E，则u在线性序列中出现在v之前。 　 通常，这样的线性序列称为满足拓扑次序的序列，简称 拓扑序列 。 注意： 　 ①若将图中顶点按拓扑次序排成一行，则图中所有的有向边均是从左指向右的。 　 ②若图中存在有向环，则不可能使顶点满足拓扑次序。 　 ③一个DAG的拓扑序列通常表示某种方案切实可行。 (Topological sort In a directed acyclic graph G topological sort, is all vertices will G formed a linear sequence, make diagram post Meaning a pair of vertex u and v, if u, v ∈ E, then u in linear sequence in which they appear in v before. Usually, such linear sequence sequence of topological order called meet, abbreviation topology sequence. Note: (1) if the diagram according to the topology order line vertices, then figure all from left to right edge are pointing. (2) if the figure to exist in the ring, is impossible to have the vertex meet topological sequence. (3) a DAG topological sequence usually expressed some scheme is feasible. )

八皇后问题，用C语言实现，在VC++6.0环境中可以运行！92种答案(Eight queens problem)