prim

该代码实现了深拷贝的问题，对于深拷贝进行了一系列的介绍，并且显示其与浅拷贝的区别。(A deep copy of the code issues a series of deep copy for presentation, and shows the difference between a shallow copy.)

数据结构 堆栈 实现了以下功能： cout<<"----------------主菜单---------------"<<endl <<"* 1.建立 *"<<endl <<"* 2.输出 *"<<endl <<"* 3.判断栈是否为空 *"<<endl <<"* 4.栈的长度 *"<<endl <<"* 5.输出栈顶元素 *"<<endl <<"* 6.进栈 *"<<endl <<"* 7.出栈 *"<<endl <<"* 8.遍历 *"<<endl <<"* 9.数制转换 *"<<endl <<"* 10.清空 *"<<endl <<"* 11.销毁 *"<<endl <<"* 12.退出 *"<<endl <<"--------------------------------------"<<endl<<endl (data structure stack)

根据所选定的字符顺序，按照从大到小的规则，对字符进行插入排序，(Insert and sort characters)

C语言课程设计例子，迷宫的实现，包括了需求分析，概要设计，详细设计，测试，源代码等(C language curriculum design example, the realization of the maze, including requirements analysis, preliminary design, detailed design, testing, source code, etc.)

东北大学数据结构实验指导书,2014级东北大学软件学院软件工程专业(Experimental data structure, guide books, Northeastern University, Northeastern University School of Software 2014 Software Engineering)

这是一个简单的银行模拟系统 1、 客户的到达时间随机 2、 客户需要处理的业务随机（不同业务处理的平均长度不同，例如：取款时间较短，开户和销户时间较长） 3、 处理客户业务所需时间随机（在一定范围内） 4、 使用文本文件记录每个客户到达时间、业务处理时间、业务结束时间 5、 动态显示（刷新时间可调）目前每个窗口累计处理客户数量、等待人数，每个窗口的平均业务处理时间，不同业务类型业务的累计办理量。 (This is a simple bank simulation system 1 customer arrival time random 2, customers need to deal with the business of random (the average length of the different business processes, such as: the withdrawal shorter, longer to open an account and cancel the account) 3, the time required to deal with customer service random (within certain limits) 4, using a text file to record each customer arrival time, business processing time, the business end of time 5 dynamically display (refresh time is adjustable) each window is accumulated to handle the number of customers waiting for the number the average business processing time of each window, different type of business operations total for the amount.)

数据结构的一些简单的排序算法，有利于初学者学习。(Data structure of some simple sorting algorithm is conducive to beginners learning.)

Hanoi塔问题非递归算法实现，几个具体的实现算法(Tower of Hanoi non-recursive algorithm, the realization of a number of specific algorithms)

数据结构课程作业，查找算法。用哈希算法下实行查找(Data structure course work, search algorithm. Under the hash algorithm used to find)

参加运动会的 个学校编号为 。比赛分成 个男子项目和 个女子项目，项目编号分别为 和 。由于各项目参加人数差别较大，有些项目取前五名，得分顺序为7，5，3，2，1；还有些项目只取前三名，得分顺序为5，3，2。写一个统计程序产生各种成绩单和得分报表。 2、要求产生各学校的成绩单，内容包括各校所取得的每项成绩的项目号、名次（成绩）、姓名和得分；产生团体总分报表，内容包括校号、男子团体总分、女子团体总分和团体总分。 3、测试数据：对于 ， ， ，编号为奇数的项目取前五名，编号为偶数的项目取前三名，设计一组实例数据。 (The school serial number participating in Games is. Competition divides into men s event and women s event , the project serial number parts for the sum. The difference is bigger since every project participates in a number , some projects choose the first five , score order is 7 , 5 , 3 , 2 , 1 Still have some of projects taking the first three places , score only being 5 , 3 , 2 in proper order. Write a form for report counting procedure producing the various school report card and score. 2, demands the school report card producing every school , content includes every achievement project number , position in a name list (achievement) , full name and score per got by school Produce the group total points form for report , content including the school number , male person group total points , woman group total points and group total points. 3, testing data: Be that the odd number project chooses the first five to the serial number, the serial number is that the even number project c)