登录
首页 » matlab » rectangular-filter

rectangular-filter

于 2014-09-08 发布 文件大小:1KB
0 243
下载积分: 1 下载次数: 1

代码说明:

  The program contains a rectangular window

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • KalmanFilter
    说明:  收藏了两篇关于Kalman滤波器的经典教程,一篇是英文原版,令一篇是翻译本,对初学者很有帮助。(Kalman Filter )
    2009-08-05 09:57:51下载
    积分:1
  • MinTV_Test
    采用MinTV算法对图像进行处理,用MinTV恢复算法+牛顿迭代法实现压缩感知对图像的处理。(MinTV algorithm using image processing, with MinTV recovery algorithm+ Newton iteration method to achieve compression perception of the image processing.)
    2010-05-31 11:13:41下载
    积分:1
  • Image-AVI
    包括两个MATLAB程序,一个读取AVI视频,并转换成一帧帧图片;两一个程序读取图片,并把这些图片转换成视频。(Consists of two MATLAB program, a read AVI video, and convert it into a frame picture 21 program reads the image and put these pictures into video.)
    2010-08-25 15:21:32下载
    积分:1
  • communicationsignalprocessing
    说明:  通信信号处理中的七阵元四信号元DOA估计,方法有CAPON、MUSIC、ESPRIT法(Communications signal processing array element seven million four signal DOA estimation, methods have CAPON, MUSIC, ESPRIT method)
    2008-09-04 10:34:29下载
    积分:1
  • pk_abc_dq
    pk_abc_dq coordinate converter
    2012-09-22 04:45:23下载
    积分:1
  • Area-of-solving
    利用matlab对图像所感兴趣的区域进行面积计算并且求解(Use matlab image of the region of interest and area calculations carried out to solve)
    2013-11-25 16:22:26下载
    积分:1
  • soft_viterbi_final.m
    Soft Viterbi decoding algorithm for reed solomon.
    2014-02-20 00:48:55下载
    积分:1
  • tftb2002toolbox
    matlab工具包,非常有用的信号时频分析工具,stft,doppler(matlab toolkit, a very useful time-frequency analysis tools, stft, doppler)
    2009-10-21 21:13:09下载
    积分:1
  • supercontinuum
    说明:  这些文章讲述了分步傅里叶方法,通过这些方法可以数值解非线性薛定谔方程,并且模拟光在光纤中传输随距离变化的状态,是学习光传输比较好的资料(The article was about a split-step Fourier method, numerical solution of these methods can be non-linear Schrodinger equation, and simulation of optical fiber transmission in the state of change with distance, is to learn good information on optical transmission)
    2011-03-30 20:59:58下载
    积分:1
  • NR_power-Flow
    x0 = ones(2,2) Make a starting guess at the solution options = optimset( Display , off ) Turn off Display [x,Fval,exitflag] = fsolve(@myfun,x0,options) The solution is x = -0.1291 0.8602 1.2903 1.1612 Fval = 1.0e-009 * -0.1619 0.0776 0.1161 -0.0469 exitflag = 1 and the residual is close to zero. sum(sum(Fval.*Fval)) ans = 4.7915e-020
    2014-02-22 08:37:54下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载