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GMWB123
Modeling Variable Annuities with MATLAB
- 2010-10-25 05:32:56下载
- 积分:1
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Archive
matlab一些常用的命令和函数,还包括一些MATLABweb在线平台的资料(matlab some commonly used commands and functions, including some MATLABweb information online platform)
- 2010-10-26 19:21:26下载
- 积分:1
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LMS
利用LMS算法来进行盲信号分离处理的程序(Using the LMS algorithm for blind signal separation processing procedures)
- 2013-10-28 16:20:04下载
- 积分:1
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GB-SAR
地基SAR基于两个点的形变检测,通过RD算法进行方位向压缩和距离向压缩,得到两幅图片,然后将这两幅图进行相位干涉得到形变量(SAR ground deformation detection based on two points, through RD algorithm azimuth compression and range compression to obtain two images, then these two figures to give shape variable phase interference)
- 2020-11-26 20:29:31下载
- 积分:1
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signal
自编的几个关于数字信号基本运算的程序,由此可以大大扩展信号运算的自由性与简洁性。(wrote several digital signal on the basic operations procedures, It can be greatly expanded signal operation and the freedom of simplicity.)
- 2007-07-07 15:13:08下载
- 积分:1
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particalswarmoptimization
一个使用matlab语言编写的粒子群算例,对初学者很有用(a example of particle swarm optimization)
- 2009-10-13 20:02:00下载
- 积分:1
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simulink-for-beginners
说明: simulink工具箱的常见问题分析以及开发过程详解,初学适用(simulink toolbox of common problems and the development of Elaboration on the Course, for beginner)
- 2010-04-18 11:54:54下载
- 积分:1
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labColorcut
基于L*A*B空间的色彩分割,可以直接运行,开发环境最好是MATLAB2009(COLOR CUT BASED ON LAB)
- 2010-05-25 13:40:55下载
- 积分:1
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example4_4
例4:在sinc(t)信号中叠加噪声,分析对应频谱
fs=100 采样频率,必须大于两倍基带信号最高频率
ts=1/fs 采样时间间隔
T=2 时间窗大小
(
x=x+0.1*randn(1,N)
x=awgn(x,-10, measured )
figure
plot(t,x)
title( 时域信号图 )
xlabel( t /s )
y=fft(x,N)
figure
if mod(N,2)~=0
N=N-1
end
f=linspace(0,fs/2,N/2)
plot(f,abs(y(1:N/2))*2/N)
title( 叠加噪声的sinc(t)信号频谱 )
xlabel( f /Hz )
figure
y0=y(1:N/2)
P=y0.*conj(y0)/N
P=10*log10(P)
plot(f,P)
title( 功率谱 )
xlabel( f /Hz )
)
- 2010-05-25 20:59:03下载
- 积分:1
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c9_estimatepi
%File: c9_estimatepi.m
%有5个pi的估计,每一个都是基于500次重复随机试验,所得的pi的五个估计值用以下向量表示
%pi的估计值=[3.0960 3.0720 2.9920 3.1600 3.0480]
%如果对5个结果进平均,则pi的估计值=3.0736,这样的结果等价于2500次的试验结果。( File: c9_estimatepi.m have 5 pi estimates are based on a randomized trial to repeat 500 times the income of the five estimated value of pi with the following vector, said the estimated value of pi = [3.0960 3.0720 2.9920 3.1600 3.0480] if the results into an average of 5, then the estimated value of pi = 3.0736, so the result is equivalent to 2500 times the test results.)
- 2006-11-05 10:30:13下载
- 积分:1