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Highboostfilters
high boost filter in matlab
- 2009-06-29 15:45:56下载
- 积分:1
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E_Hedge
金融工程中欧式买权和欧式买权的评价, 希望能够帮助到大家(Financial engineering appraisal rights and European Continental buy the right to buy, and I hope to be able to help you)
- 2015-04-20 13:44:22下载
- 积分:1
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matlab-shiyongjiqiao
matlab的实用技巧,是一些常见的但不好解决的问题的解答方法(matlab the practical skills, some common, but not solve the questions)
- 2012-08-15 15:26:40下载
- 积分:1
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yzd1111
电机转子断条时,使用ansoft maxwell建立的异步电机断条模型,数据需要matlab处理(Motor broken rotor bars, using the model of the induction motor broken bars created ansoft maxwell, data need matlab processing)
- 2013-04-05 11:13:39下载
- 积分:1
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matlab--newton-33node-powerflow
matlab配网33节点用牛顿拉夫舜法求解电网潮流计算。(matlab distribution network node 33 Ralph Shun calculated using Newton method for solving power flow.)
- 2014-12-23 12:40:45下载
- 积分:1
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MAT-LAB-FILE
MAT lab source code need
- 2014-01-30 22:40:50下载
- 积分:1
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wangmendel
one of the most important areas for
the application of Fuzzy Set Theory as developed
by Zadeh in 1965 are Fuzzy Rule-Based Sys-
tems (FRBSs).The ad hoc data-driven RB generation process
proposed by Wang and Mendel in [14] has been
widely known because of its simplicity and good
performance.
- 2010-07-07 13:10:53下载
- 积分:1
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matlab2
这是单变量寻优的作业程序,有仿真结果,很完整,希望能帮到大家。(This is the single-variable optimization of the operating procedures, there are simulation results, it is complete, I hope to help everyone.)
- 2008-04-23 16:22:25下载
- 积分:1
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delNum
给定n位整数任意去掉其中k<=n位,剩下的数字按原次序排列组成一个新的正整数,且这个正整数最小(Given an arbitrary n-bit integers to remove where k < = n bits, the remaining number of original order of the formation of a new positive integer, and that this is the smallest integer)
- 2010-01-03 21:43:20下载
- 积分:1
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LDPCcode
利用函数MadHG生成规则LDPC码的校验矩阵H,其行重为6,列重为3,行数为列数一半(行数越大越好),H中任意两列没有围长为4的圈,并得到H对应的生成矩阵G,可以保证mod(G*H ,2)=0。使用方法为:[H,G] = MadHG(m,n,x),x= 1(得到的G左半部分为单位阵) or 2(G右半部分为单位阵),(use function MadHG Generation rules LDPC check matrix H, re-6, series of three, out for a few half of the number (A bigger the better), H 2 arbitrary no girth of the four circles, H counterparts and with the formation of matrix G, we can be assured of mod (G* H, 2) = 0. To be used : [H, G] = MadHG (m, n, x), x = 1 (the G part of the Left Front units) or 2 (G right half of the units RUF),)
- 2007-05-12 10:49:48下载
- 积分:1