SplitADT

约瑟夫问题，用数据结构的循环链表实现约瑟夫问题的解答(Joseph problems，30 people in a circle, and inspires us with a circular chain to said. Can use structure array to make a cycle chain. The structure has two members, one for pointing down a pointer to a circular chain )

主要是DIJKSTRA经典算法，可以作为单个算法来读，也可以调用。(DIJKSTRA mainly classical algorithm can be read as a single algorithm can also be called.)

该ppt包含了栈和队列的数据结构及基本操作，同时还有栈的举例(This ppt contains the stack and queue data structure and basic operation, as well as examples of the stack)

本系统采用C语言编写，利用邻接链表实现最短路径问题，关键路径问题等(The system uses the C language, using adjacency list realize the shortest path problem, critical path issues)

单链表中的数据元素含有三种字符（字母、数字、其他字符），算法实现构造三个循环链表，是每个循环链表中只含有同一类字符，且利用原表中的结点空间作为这三个表的结点空间。(Singly linked lists of data element contains three characters (letters, Numbers and other characters), the algorithm constructs three circular linked list, each cycle list contains only the same type of character, and make use of the primary node space in a table as a node of the three table space.)

哈希表 数据结构课程设计 1.1问题描述 针对自己的班集体中的“人名”设计一个哈希表，使得平均查找长度不超过R，完成相应的建表和查表程序。 1.2基本要求 假设人名为中国姓名的汉语拼音形式。待填入哈希表的人名共有30个，取平均查找长度的上限为2。构造哈希函数，用链表法处理冲突。 1.3测试数据 读取熟悉的30个人的姓名作测试。(Hash table Data Structure Course Design 1.1 Description of the problem For their own class group of the "names" to design a hash table, making the average search length does not exceed R, the completion of construction of tables and look-up table corresponding procedures. 1.2 Basic requirements Assuming the name of the person called Chinese pinyin form. To be filled into a hash table names a total of 30, taking the average search length of the upper limit of 2. Construct a hash function, treatment with a list of conflict. 1.3 Test Data Read the familiar names of 30 individuals tested.)

邻接表存储图，然后进行深度优先遍历及广度优先遍历。(DFS,adjacent matrix)

找出数组A中最长的递增序列的长度，使用动态规划算法，复杂度为O(N*N)。(Find the longest increasing sequence)

按照一定的输入求出二叉树的层次遍历，输出相应的结果(Calculated in accordance with the input binary tree traversal of the hierarchy, the output of the corresponding results)

说明：  在给定的字母中，用c++来实现字母的排序(In a given letter, the use of c++ to implement the letter of the sort)