maze

Hanoi塔问题非递归算法实现，几个具体的实现算法(Tower of Hanoi non-recursive algorithm, the realization of a number of specific algorithms)

单链表程序 可执行单链表的基本功能 创建 删除 查找 存取 等等(Basic functions to create a single linked list program executable single linked list delete find access)

描述：足球俱乐部包括球员、普通行政人员。球员有姓名、年龄、能力、年薪、转会费、进球总数、服役年限等重要参数；普通行政人员有姓名、年龄、能力、年薪等参数。你需要给相关管理机构开发一个管理程序，实现对众多足球俱乐部管理的基本功能。具体功能包括： a) 俱乐部的增删改查，俱乐部的属性包括名称、现金、其下人员； b) 可以对所有球员的各项属性进行简单搜索，支持输入多个条件，条件之间用&&连接，例如： i. “年龄不大于25且服役年限大于5年且进球数大于100的球员”，查询表达式：!(@age>25) && @experience>5 && @kick>100 c) 支持球员在不同俱乐部间的买卖，买卖需符合以下条件：作为买方的俱乐部的现金>=球员的转会费，交易完成后，卖方将得到转会费。 要求： d) 必须采用面向对象的方式，使用类组织数据结构，并注意类的继承关系； e) 在题目要求基础上可以自行扩展功能，提供扩实用扩展功能者适当加分（加分不超过5分）。 (Description: Football club including players, general administrative staff. Player name, age, ability, salary, transfer fee, total number of goals, service life and other important parameters ordinary administrative staff name, age, ability, salary and other parameters. You need to give the relevant management agencies to develop a management program to achieve the number of football club management s basic functions. Specific features include: a) the club CRUD, the name of the club s property, including cash, under which personnel b) all players can perform a simple search of the property, supports input multiple conditions with && connection between conditions, for example: i. "Age is not greater than 25 and greater than 5 years service life and goals more than 100 players," query expression:! (@ age> 25) && @ experience> 5 && @ kick> 100 c) Support the players traded between different clubs, the sale subject to the following conditions: As a buyer s club cash> = pl)

.h文件。c++中的复数类，能够直接完成基本四则运算，输入输出流，完成一定范围内的比较运算(. H file. c++ classes in the plural, to directly perform basic arithmetic, input and output streams, to complete a range of comparison operators)

该代码实现了深拷贝的问题，对于深拷贝进行了一系列的介绍，并且显示其与浅拷贝的区别。(A deep copy of the code issues a series of deep copy for presentation, and shows the difference between a shallow copy.)

数据结构二叉树，及其遍历，镜像，输出等相关操作C++源码。(Binary tree data structure and its traversal, mirror, output the operation C++ source.)

找出数组A中最长的递增序列的长度，使用动态规划算法，复杂度为O(N*N)。(Find the longest increasing sequence)

编写一个将二叉树的所有叶子结点从左向右链接成单链表的算法(Write a binary tree leaf nodes from left to right links into a single linked list algorithm)

清（英文）常见数据结构，代码实现，值得下载，值得分享(Qing (English) common data structure, code implementation, worth downloading, worth sharing)

用分治算法（O(nlogn)复杂度）实现寻找n个点中最邻近点对,输出为最邻近距离的平方(Looking for n points nearest point, the output of the nearest neighbor distance squared using the divide-and-conquer algorithm (O (nlogn) complexity))