huffman

使用C++/C语言实现的红黑树，对于数据结构的学习有所帮助。(Use red-black tree C++/C language for learning data structures helpful.)

约瑟夫环（约瑟夫问题）是一个数学的应用问题：已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1，最后结果+1即为原问题的解。 (Josephus (Josephus problem) is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n respectively) sitting around a round table. From the number of people gettin k, number of the m man out of the line he s the next person and a number of gettin number to m the man was out of the line and so the law is repeated until the round table were all out of the column. We numbered 0 ~ n-1, the final result is the original problem solution+1 usually solve these problems.)

算法课程设计 分治法解决循环赛日程表 源代码+word报告+答辩PPT(Curriculum design of divide and conquer algorithm to solve a round robin schedule report+ source code+ word reply PPT)

八皇后算法，用的是最简单的穷举法，在VC++6.0上编写的。(Eight Queens algorithm, using the simplest method of exhaustion, in VC++6.0 written on.)

找出数组A中最长的递增序列的长度，使用动态规划算法，复杂度为O(N*N)。(Find the longest increasing sequence)

数据结构与算法分析的 C++检索代码，很经典(the code of Data structure)

数据结构课程设计时，所需的封面及任务书版面，希望对大家有点用！(Curriculum design data structure, the necessary task of the book cover and layout, in the hope that we are a bit used!)

将一组数组转换为哈夫曼编码，使用数据结构中的二叉树功能实现(Convert an array to Haffman code)

建立链表的算法： 新节点链入表尾建立链表： 动态分配第一个节点变量； 用指针head 妥善保存链表第一个节点的地址值； 依次动态分配一个新节点变量； 将上一个节点的指针域指向新生成的节点； 循环3),4)步骤，直到所有节点均连入链表； 将最后一个节点的指针域赋值为0； (Establish the list of algorithms: The new node links footer build list: Dynamic allocation of the first node variable Keep the list head pointer of the first node address value In order to dynamically allocate a new node variable The domain of a node pointer to the new generation of nodes Cycle 3), 4) step, until all nodes are connected to the chain Pointer field will last node assigned to 0 )

选择型结构c语言编程 (Choose the type of structure of C language programming)