Airlinereservationsystem

这个代码是STRING类的声明及实现,因为我认为C++类库中的string类比较庞大,找一个函数需要很长时间,所以用一个简单明了的代替之.(STRING kind of statement and realized, because I think the C library string of relatively large, a function for a very long time. Therefore, the use of a simple and straightforward replaced it.)

此程序用于解决8皇后问题，运行后输出8皇后问题的所有解(This program is used to solve the 8 queens problem, all solutions of 8 queens problem output operation.)

说明：  定义一个类SortArray继承自MyArray，在该类中定义函数sort实现排序功能。 定义一个类ReArray继承自MyArray，在该类中定义函数reverse实现逆转功能。 定义一个类AverArray继承自MyArray，在该类中定义函数Aver实现求解整数的平均值。 定义NewArray类，同时继承了SortArray、ReArray和AverArray，使得NewArray类的对象同时具有排序、逆转和求平均值的功能。在继承的过程中声明为虚基类，体会虚基类在解决二义性问题中的作用。 (Define a class SortArray inherited from MyArray, defined in the class sorting function sort implementation. Define a class ReArray inherited from MyArray, define the function in reverse to achieve such reversal function. Define a class AverArray inherited from MyArray, defined in the class to solve integer function Aver achieve the average. Defined NewArray class, and inherits SortArray, ReArray and AverArray, making the object of both NewArray class sorting, reversing, and the mean value of the function. In the process of succession declared as virtual base classes, virtual base class experience in resolving ambiguities of the role.)

带权有向以及无向图的各种操作，适合数据结构初学者使用，是图那一章的重点(belt and the right to have no plans to the various operations, data structure suitable for beginners, is the chief focus of the chapter)

八皇后问题，用C语言实现，在VC++6.0环境中可以运行！92种答案(Eight queens problem)

迷宫算法，1代表可以通过，0代表墙壁，自动找寻路线(Maze algorithm, 1 can pass 0 for the walls, automatically find routes)

给定n种物品和一背包。物品i的重量是wi>0,价值为vi>0,背包的容量为c。选择装入背包的物品，使得装入背包中物品的总价值最大。(Given n kinds of goods and a backpack. Weight of the item i is wi> 0, the value of vi> 0, knapsack capacity c. Select the items into the backpack, so into the backpack of items in the total value of the maximum.)

题意:给你n个数,求出两两组合的最大公约数 类似打素数表的做法 (Meaning of the questions: to give you the number n, find greatest common divisor of a similar combination twenty-two hit the practice table of prime numbers)

数据结构 银行模拟问题 (Bank of simulation data structure problem)

克鲁斯卡尔算法思想.cpp int seekedge(EDGE * (&a), int n) void bubble(EDGE * (&a), int size) void searchandjoin(EDGE * (&a1), int k) // a1是图边集头指针，a2是最小生成树边集的头指针，k为所要删的边 void storepicture(EDGE * (&a), int n, VERTEX *b, int m) (Thinking of Kruskal algorithm. Cpp int seekedge (EDGE* (& a), int n) void bubble (EDGE* (& a), int size) void searchandjoin (EDGE* (& a1), int k) // a1 edge set is the first pointer map, a2 is the minimum spanning tree of the first indicators margination, k for the edges to be deleted void storepicture (EDGE* (& a), int n, VERTEX* b, int m) )