algorithm

约瑟夫环（约瑟夫问题）是一个数学的应用问题：已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1，最后结果+1即为原问题的解。 (Josephus (Josephus problem) is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n respectively) sitting around a round table. From the number of people gettin k, number of the m man out of the line he s the next person and a number of gettin number to m the man was out of the line and so the law is repeated until the round table were all out of the column. We numbered 0 ~ n-1, the final result is the original problem solution+1 usually solve these problems.)

通过学习奥赛培训课程，利用回溯加递归的编程技巧完成的迷宫问题(Training courses through learning Orsay, plus use of recursive programming skills back to complete the maze problem)

说明：  定义一个类SortArray继承自MyArray，在该类中定义函数sort实现排序功能。 定义一个类ReArray继承自MyArray，在该类中定义函数reverse实现逆转功能。 定义一个类AverArray继承自MyArray，在该类中定义函数Aver实现求解整数的平均值。 定义NewArray类，同时继承了SortArray、ReArray和AverArray，使得NewArray类的对象同时具有排序、逆转和求平均值的功能。在继承的过程中声明为虚基类，体会虚基类在解决二义性问题中的作用。 (Define a class SortArray inherited from MyArray, defined in the class sorting function sort implementation. Define a class ReArray inherited from MyArray, define the function in reverse to achieve such reversal function. Define a class AverArray inherited from MyArray, defined in the class to solve integer function Aver achieve the average. Defined NewArray class, and inherits SortArray, ReArray and AverArray, making the object of both NewArray class sorting, reversing, and the mean value of the function. In the process of succession declared as virtual base classes, virtual base class experience in resolving ambiguities of the role.)

约瑟夫环，数据结构算法，挺有意思，看看，看看(ysphdfgfgf)

学数据结构自己总结的东西，希望对大家有所帮助。(Learn data structure sum things up, we want to help.)

大学计算机专业，数据结构中的改进的KMP算法，C++编写。(University computer science, data structures to improve the KMP algorithm, C++ written.)

该代码实现了深拷贝的问题，对于深拷贝进行了一系列的介绍，并且显示其与浅拷贝的区别。(A deep copy of the code issues a series of deep copy for presentation, and shows the difference between a shallow copy.)

主要用栈和树求解骑士问题，用C++语言编写的(The main stack and tree Cavalier Problem Solving with C++ languages)

设计、编写和调试面向对象C++程序，实现任意两个同类数据比大小 的通用函数（模板），涵盖普通数值型数据之间的比较、两个字符串之间的比较 （按字典序）、两个复数之间的比较（按模大小）等，并通过主函数加以调用和 测试。(Design, writing and debugging of object-oriented C++ procedures to achieve similar data than the size of any two generic functions (template), covering general comparison between numerical data, the comparison between the two strings (lexicographically), two Comparison between complex numbers (modulo the size), and through the main function to be invoked and tested.)

实现经典问题老鼠迷宫，并用坐标将路径显示出来(Achieve classic problem rat maze, and coordinate with the path displayed)