X_bit0mintest

总结了10种排序的方式。用代码加以实现。(the ten way of Line up a preface)

为了点分 求分下载好麻烦 c++二叉排序树(In order to find points dotted download good trouble c++ binary sort tree)

背包算法的c++简单实现，很有用的，可以看看(Knapsack algorithm)

COM中使用SAFEARRAY数组例程，代码中给了两种数组的用法，一种是字符串数组，另一种是自定义数据结构数组。 (use COM SAFEARRAY array routines, a code for the use of two arrays, a string array, and the other is from the definition of array data structure.)

使用C语言完成党的霍夫曼编码，主要使用树的数据结构，作为巩固数据结构的练习(Using the C language to complete the party' s Huffman coding, the main use of the tree data structure, data structure as a consolidation exercise)

说明：  KMP算法的具体实现，能够在O(n+m)时间内找出字串在父串中的位置，n为父串长度，m为字串长度(KMP in the proposed algorithm, can be O (n+ m) time to find the string in the parent string position, n the parent string length, m for the string length)

This is a C++ code. It finds out if the tree is a binary search tree (BST)or not, where the BST is one of data structures types.

哈希表 数据结构课程设计 1.1问题描述 针对自己的班集体中的“人名”设计一个哈希表，使得平均查找长度不超过R，完成相应的建表和查表程序。 1.2基本要求 假设人名为中国姓名的汉语拼音形式。待填入哈希表的人名共有30个，取平均查找长度的上限为2。构造哈希函数，用链表法处理冲突。 1.3测试数据 读取熟悉的30个人的姓名作测试。(Hash table Data Structure Course Design 1.1 Description of the problem For their own class group of the "names" to design a hash table, making the average search length does not exceed R, the completion of construction of tables and look-up table corresponding procedures. 1.2 Basic requirements Assuming the name of the person called Chinese pinyin form. To be filled into a hash table names a total of 30, taking the average search length of the upper limit of 2. Construct a hash function, treatment with a list of conflict. 1.3 Test Data Read the familiar names of 30 individuals tested.)

猴子选大王是个重要问题猴子选大王是个重要问题猴子选大王是个重要问题(houzixuandawang)

使用三叉链表实现的哈夫曼树,统计inputfile1.txt中各字符的出现频率，并据此构造Huffman树，编制Huffman 码；根据已经得到的编码，对01形式的编码段进行译码。 具体的要求： 1．将给定字符文件编码，生成编码，输出每个字符出现的次数和编码； 2．将给定编码文件译码，生成字符，输出编码及其对应字符。 (Emergence of the frequency of each character in the trigeminal lists using the Huffman tree, statistics inputfile1.txt, and accordingly the Huffman tree structure, preparation of Huffman code according to the coding has been. 01 to form the code segment for decoding. Specific requirements: 1 coding the given character file, generating the encoding, and outputting the number and encoding of each character 2 will be given the encoding file decoding, generating the character, the output code and its corresponding character.)