datastr

本代码是通过C语言来实现贪心算法求着色问题,包括具体问题和实现代码(This code is the C language to implement the greedy algorithm for the coloring problem, including specific issues and the implementation code)

好用的平衡二叉树类库，C++类库编写， 好用的平衡二叉树类库，C++类库编写(AVL tree implementation for C++)

约瑟夫环（约瑟夫问题）是一个数学的应用问题：已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1，最后结果+1即为原问题的解。 (Josephus (Josephus problem) is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n respectively) sitting around a round table. From the number of people gettin k, number of the m man out of the line he s the next person and a number of gettin number to m the man was out of the line and so the law is repeated until the round table were all out of the column. We numbered 0 ~ n-1, the final result is the original problem solution+1 usually solve these problems.)

说明：  在给定的字母中，用c++来实现字母的排序(In a given letter, the use of c++ to implement the letter of the sort)

关于Arnoldi算法的今年来的中文资料，希望能够给有兴趣编写这方面算法的人提供帮助(Arnoldi algorithm on the Chinese data this year, hoping to write this algorithm are interested in helping people)

迷宫求解一般采用“穷举法”，逐一沿顺时针方向查找相邻块（一共四块－东(右)、南(下)，西(左)、北(上)）是否可通，即该相邻块既是通道块，且不在当前路径上。用一个栈来记录已走过的路径栈是限定仅在表尾(top)进行插入或删除操作的线性表。(Maze solving generally use the " exhaustive" one by one to find adjacent blocks in a clockwise direction (a total of four- East (right), South (down), West (left), North (on)) whether to pass, that the both channel blocks adjacent blocks, and not in the current path. Use a stack to record the path traversed stack is limited only in the tail (top) to insert or delete a linear form.)

说明：  设计济南大学校园平面图，所含的景点不少于10个。以图中顶点表示校内各景点，存放景点名称、代号、简介等信息；以边表示路径，存放路径长度等相关信息。 为来访客人提供图中任意景点相关信息的查询。 为来访客人提供图中任意景点的问路查询，即查询任意两个景点之间的一条最短的简单路径。 选作内容： 求校园的关节点。 提供图中任意景点查询，即求任意两点间的所有路径。 校园导游图的景点和道路的修改扩充功能。 扩充道路信息，如道路类别，沿途景色等级，一直可按客人所需分别查询人行路径或车行路径或观景路径。(Design jinan university campus plan, contains at least 10 spots in each vertex said in scenic spots, deposit attractions at the information such as the code name introduction On the path, deposit path length said related information )

哈夫曼树，基本的数据结构，用来编码和解码、用数组作为存储结构实现，

八皇后问题，用C语言实现，在VC++6.0环境中可以运行！92种答案(Eight queens problem)

说明：  线性表的基本运算及多项式的算术运算在顺序表泪SeqList 中增加成员函数void Reverse()实现顺序表的逆置 (Linear form the basic arithmetic operations and the polynomial form in order to increase tear SeqList member function void Reverse () to achieve the inverse order of the table set)