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histogram_equalization

于 2007-04-12 发布 文件大小:609KB
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代码说明:

  有关直方图均衡化原理的matlam源程序(the histogram equalization principle source of matlam)

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  • base
    1.分别在两个图中画出δ(n)和δ(n-2),其中-10≤n≤10,画出U(n)其中-10≤n≤10。 2.分别在两个图中画出x1(n)=cos(2π×20×0.01×n),0≤n≤10和x2(n)=(0.8)n,1≤n≤6。 3.由上一题,计算y(n)=x1(n)+x2(n),并画图。(1. Draw the figure at two δ (n) and δ (n-2), where-10 ≤ n ≤ 10, draw the U (n) where-10 ≤ n ≤ 10. 2. Respectively in the two Draw the figure x1 (n) = cos (2π × 20 × 0.01 × n), 0 ≤ n ≤ 10 and x2 (n) = (0.8) n, 1 ≤ n ≤ 6. 3. from the previous question, calculate y (n) = x1 (n)+ x2 (n), and drawing.)
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