mpc

matlab数字信号与应用源代码7，对初学者有帮助(and application of digital signal matlab source code 7, help for beginners)

MATLAB 中的插值程序，含说明与范例，并比较四种插值方法的结果。(MATLAB in the interpolation process, including description and examples, and compare the results of four kinds of interpolation methods.)

BP网络结构设计 实现对大气环境质量评价问题，内含PPT(BP network design and implementation issues of air quality assessment, containing PPT)

ISODATA法分类IRIS数据集，压缩包中包括两个.m文件，运行provaisodata_4D.m可直接分类。或者通过isodata_4D.m设置参数也可以得到结果。程序有详细注释，很容易懂。最后结果既有文字描述，也有图形输出。(ISODATA classification method IRIS data set, compressed package includes two. M files, run provaisodata_4D.m direct classification. Or set the parameters by isodata_4D.m can get results. Procedures detailed notes, it is easy to understand. Final results of both the written description, there are graphical output.)

这里给出几幅多聚焦图像，为大家做图像融合处理，一共两组图像(Here are the pieces of multi-focus image, for everyone to do image fusion, a total of two sets of images)

DDA line Algorithm for draw line by matlab

微分方程网格生成 计算传热学 离散方法 自适应网格(The differential equation of grid generation)

利用matlab的m函数和simulink达到题目中的要求(Use matlab m-function and simulink meet the requirements of the title)

matlab 30个经典案例分析，内容丰富经典，是初学者的好帮手(30 matlab classic examples)

产生右图所示图像f1(m,n)，其中图像大小为256×256，中间亮条为128 ×32，暗处=0，亮处=100。对其进行FFT： ① 同屏显示原图f1(m,n)和FFT(f1)的幅度谱图； ② 若令f2(m,n)=（-1）m+n f1(m,n)，重复以上过程，比较二者幅度 谱的异同，简述理由； ③ 若将f2(m,n)顺时针旋转90 度得到f3(m,n)，试显示FFT(f3)的幅 度谱，并与FFT(f2)的幅度谱进行比较； ④ 若将f1(m,n) 顺时针旋转90 度得到f4(m,n)，令f5(m,n)=f1(m,n)+f4(m,n)，试显 示FFT(f5)的幅度谱，并指出其与FFT(f1)和FFT(f4)的关系； ⑤ 若令f6(m,n)=f2(m,n)+f3(m,n)，试显示FFT(f6)的幅度谱，并指出其与FFT(f2)和 FFT(f3)的关系，比较FFT(f6)和FFT(f5)的幅度谱。(Generating an image f1 (m, n) shown in the figure, wherein the image size is 256 256, the intermediate light bar 128 32 0 = dark, bright Department 100. Its FFT: ① screen display picture f1 (m, n) and the FFT (f1) of the amplitude spectrum ② If so f2 (m, n) = (-1) m+n f1 (m, n), repeat The above process, comparing the amplitude spectrum of the similarities and differences between the two, brief reasons ③ If f2 (m, n) 90 degrees clockwise to get f3 (m, n), try to display FFT (f3) the amplitude spectrum and with the FFT (f2) comparing the amplitude spectrum ④ If f1 (m, n) obtained by 90 degrees clockwise f4 (m, n), so f5 (m, n) = f1 (m, n)+f4 (m, n ), try to display FFT (f5) amplitude spectrum, and pointed out its relationship with the FFT (f1) and FFT (f4) of ⑤ If so f6 (m, n) = f2 (m, n)+f3 (m, n) and try to display the FFT (f6) amplitude spectrum, and pointed out its relationship with the FFT (f2) and FFT (f3), comparing FFT (f6) and FFT (f5) amplitude spectrum.)