wavedetect

说明：  matlab编写的小波变换程序，有很多实例，是《Matlab小波分析》（张德丰）教程的源程序，很适合学习使用。(matlab wavelet transform procedures for the preparation, there are many examples is &quot Matlab Wavelet Analysis&quot (Zhang Defeng) tutorial source code, it is suitable for learning to use.)

配网潮流前推回代法40节点的一个具体例子，直接运行即可。(A concrete example of the backward substitution method 40 nodes in the trend of the distribution network, and can be run directly.)

CMOS集成电路基础知识，CMOS集成电路的接口电路，CMOS集成电路使用注意事项 (Basic knowledge of CMOS CMOS integrated circuit, integrated circuit interface circuit, CMOS integrated circuit use matters needing attention )

matlab的滤镜 包含有2个文件 作业(matlab filter contains two file operations)

运用matlab实习动态规划中的逆序算法的例题及matlab程序，对程序也有很详细的解析说明(To use matlab internship Reverse Algorithm of dynamic programming examples and matlab program, the program is also detailed analysis)

对小波X={0,1,...,10}进行一次分解与重构(Of the wavelet X = (0,1 ,..., 10) for a decomposition and reconstruction)

Power line comunication simulator

ofdm的matlab仿真程序，对学习ofdm技术的人员来说比较实用(ofdm matlab simulation program, to learn ofdm technology officer for more practical)

产生右图所示图像f1(m,n)，其中图像大小为256×256，中间亮条为128 ×32，暗处=0，亮处=100。对其进行FFT： ① 同屏显示原图f1(m,n)和FFT(f1)的幅度谱图； ② 若令f2(m,n)=（-1）m+n f1(m,n)，重复以上过程，比较二者幅度 谱的异同，简述理由； ③ 若将f2(m,n)顺时针旋转90 度得到f3(m,n)，试显示FFT(f3)的幅 度谱，并与FFT(f2)的幅度谱进行比较； ④ 若将f1(m,n) 顺时针旋转90 度得到f4(m,n)，令f5(m,n)=f1(m,n)+f4(m,n)，试显 示FFT(f5)的幅度谱，并指出其与FFT(f1)和FFT(f4)的关系； ⑤ 若令f6(m,n)=f2(m,n)+f3(m,n)，试显示FFT(f6)的幅度谱，并指出其与FFT(f2)和 FFT(f3)的关系，比较FFT(f6)和FFT(f5)的幅度谱。(Generating an image f1 (m, n) shown in the figure, wherein the image size is 256 256, the intermediate light bar 128 32 0 = dark, bright Department 100. Its FFT: ① screen display picture f1 (m, n) and the FFT (f1) of the amplitude spectrum ② If so f2 (m, n) = (-1) m+n f1 (m, n), repeat The above process, comparing the amplitude spectrum of the similarities and differences between the two, brief reasons ③ If f2 (m, n) 90 degrees clockwise to get f3 (m, n), try to display FFT (f3) the amplitude spectrum and with the FFT (f2) comparing the amplitude spectrum ④ If f1 (m, n) obtained by 90 degrees clockwise f4 (m, n), so f5 (m, n) = f1 (m, n)+f4 (m, n ), try to display FFT (f5) amplitude spectrum, and pointed out its relationship with the FFT (f1) and FFT (f4) of ⑤ If so f6 (m, n) = f2 (m, n)+f3 (m, n) and try to display the FFT (f6) amplitude spectrum, and pointed out its relationship with the FFT (f2) and FFT (f3), comparing FFT (f6) and FFT (f5) amplitude spectrum.)

OPSOCM: Opposition based PSO with Cauchy Mutation.