zishiingkongzhi

binary searching in the code.

This is a simple code for create window

信号处理与分析，是基于gui的信号处理与分析，相关函数的应用。(Random signal analysis and Process)

24G高集成度微波雷达芯片,一发二收，可组成阵列天线，数据处理后精度可达mm级(24 GHz transceiver MMIC with one transmitter and two receiver units • Fully integrated low phase noise VCO • Switchable prescaler with 1.5 GHz and 23 kHz output • On chip power and temperature sensors • Gilbert based homodyne quadrature receiver • Single ended RF input terminals)

该工程实现2fsk的载频估计，返回2fsk两个载频估计结果。(The project is estimated to achieve 2fsk carrier frequency, return 2fsk two carrier frequency estimation results.)

常见激光雷达的重要原理 常见军用激光雷达的重要原理 激光(The principle of lidar)

RS 码译码源程序,在Visual c++下可对比4元域上的RS码进行纠错译码.(RS decoder source, in Visual c contrast under four yuan domain of RS error correction code for decoding.)

用GA算法和ACO算法在MATLAB上解决TSP问题，附有31个城市的坐标数据(Coordinate data with GA algorithms and ACO algorithm in MATLAB to solve the TSP with 31 cities)

MATLAB语言常用算法程序集，第8章 数值积分(MATLAB language commonly used algorithm for assembly, Chapter 8, numerical integration)

说明：  给定n种物品和一个背包,物品i的重量是Wi,价值是vi,被包容量是C,应该如何选择装入被包的物品,使得装入背包中物品的总价值最大?对于每种物品i,只有两种选择,装入或者不装入. 输入:第一行两个正整数n(物品数)和C(容量) 第二行n个正整数n,表示物品价值 第三行n个正整数n,表示物品重量 输出:第一行表示总价值 第二行n个数(0/1),0表示物品不装入,1表示装入 例如, 输入: 5 10 6 3 5 4 6 2 2 6 5 4 输出 15 1 1 0 0 1 (Species of a given n items and a backpack, the weight of item i is Wi, the value of vi, was packet capacity is C, should be how to choose a package of items to be loaded, the backpack load in the largest total value of goods? For each item i, there are only two options, loaded or not loaded. Input: the first line of the two positive integer n (the number of items) and C (capacity) of the second line of n positive integer n, that the value of the third line of n positive integer n, that the weight of output: the total value of the first line of the second line, said n number of (0/1), 0 that the items do not load, that load 1 for example, enter: 5,106,354,622 6 5 4 output 15 1 1 0 0 1)