snake

latex的模板，适用于各种学术论文的排版，简单易用，可操作性强。(latex template for a variety of publishing academic papers, easy to use, easy to operate.)

作为电力系统暂态，产生必要的扰动模拟信号用于分析(As a power system transient, resulting in the disturbance necessary for the analysis of analog signals)

高斯信道下QPSK仿真程序，显示了QPSK在高斯信道下误码率和信噪比的关系。(Gaussian channel under QPSK simulation program shows the relationship between QPSK Gaussian channel BER and SNR.)

read data function for project colour base image retrieval

从其他网站下载的经典蚁群算法，对初学者非常有用，请看看。(downloaded from other websites of the classic ant algorithm, very useful for beginners, please look at.)

code matlab descripteur gist matlab

说明：  自己编的付里叶变换，对学习者有很大帮助　(own series of the Fourier transform, to be of great help learners)

说明：  MATLAB 编程，用MATLAB对先进控制算法编程 并且给出一个对象对其进行仿真(MATLAB programming, using MATLAB programming for advanced control algorithms and gives an object its simulation)

仿真FBG传输特性，共三个函数，利用光纤的传数矩阵和耦合模理论，可在main函数中修改参数(Simulation FBG transmission characteristics of the three functions, the use of optical fiber transmission matrix and coupled-mode theory, the parameters can be modified in the main function)

一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。 C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。 系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)