LeastSquare

说明：  MATLAB实现的直接传输通信的统计误码率仿真。(MATLAB realization of the direct transmission of communication statistics BER simulation.)

matlab中随机生成囧字，非常不错的动画(matlab randomly generated embarrassing word, very good animation)

这是用matalab实现的EM算法，简单易用，对于理解EM算法很有用，尤其是对于初学者。(This is the EM algorithm implemented with matalab, easy to use, useful for the understanding of the EM algorithm, especially for beginners.)

高效线性整数规划求解matlab源程序，详细注释，完善测试(linear integer programming matlab source codes with detailed remarks and tests，)

matlab robotics toolbox sample

介绍了数字通信中的QPSK调制解调的原理，通过用Matlab编写脚本程序对QPSK通信系统的发射和接收过程的具体实现进行模拟仿真，绘出信号在理想信道和加噪信道中模拟传输时的时域图，并对各模块进行了频谱分析，所得到的结果与理论基本相符，对于理解QPSK系统的性能并在系统的实际应用上作进一步的设计，提供了有效的参考依据(The introduction was done with the principle of the QPSK modulation and demodulation in digital communications, a script was written by using Matlab program to carry out a simulation of the QPSK communication system ,which contains the concrete realization of transmit and receive process. The time-domain diagram is drew separately when the signal transmits in the ideal channel and in the channel with noise, spectral analysis of each module is also done, the results obtained with theoretical results in the main, which provides an effective frame of reference for understanding the performance of QPSK systems, and the practical application in the system to make further designed.)

无线通信物理层信道建模，链路衰落，LDPC编码，OFDM，及智能天线等等关于物理层的码源(Wireless communication channel modeling the physical layer, link the decline, LDPC codes, OFDM, and smart antennas, and so the source code on the physical layer)

Z=X+Y 求Z的分布 並且畫出圖 並與理論公式值做比較 (Z = X+ Y seeking to draw the map the distribution of Z and compare with the theoretical formula for the value)

基于gui的matlab完整程序，打桩机运动学仿真(gui matlab kinesiology )

Nonlinear Control Systems - Lecture 3 - September 1, 2005 Contraction Mapping Principle Consider a map T : X ! X that maps a normed linear space X back into itself. We say T is a contraction mapping if and only if for all x y 2 X there exists  where 0   < 1 and