guyoupinlvjisuan

说明：  MATLAB实现QR算法以及带位移的QR算法 求矩阵特征值(MATLAB，The realization of QR algorithm and QR algorithm with displacement Characteristic value of matrix)

adi-fdtd code in one dimensional whithout PML, with PEC ( Perfect Electric Condutor)

这是一些MATLAB中有关通信方面的simulink仿真的设计(These are MATLAB, simulink simulation of the communications aspects of the design)

cours of matlab a fiew explication and brief examples of matlab porgramation

模糊控制在调速系统上的MATLAB仿真,具有实际的意义(Fuzzy Control in the MATLAB simulation of speed control systems, has practical significance)

love波程序love波程序love波程序love波程序里面包含频谱分析(lvoe wave)

说明：  广义有序统计类恒虚警检测器（GOS-CFAR），包括广义有序平均检测（GOSCA）和广义有序最值检测（GOSGO和GOSSO）(detectors based on the general ordered statistic constant false alarm rate (GOS-CFAR) technique.)

熟悉matlab的人都会很清楚matlab中的feval()函数没法对匿名函数进行运算，当然更不可能执行当前路径之外或者说搜索路径之外的函数。还有eval只能执行字符串命令。 9 q2 u8 e" L& Y, E Z8 {然而evalf解决了上面的所有问题 (Matlab person familiar with the very clear matlab in feval () function can not be anonymous function of computing, of course, impossible to implement outside of the current path or the path outside the search function. There can only run eval command string. 9 q2 u8 e L )

　综合评判是对多种属性的事物，或者说其总体优劣受多种因素影响的事物，做出一个能合理地综合这些属性或因素的总体评判(Comprehensive evaluation of DuoZhong attributes of the things is, or the overall quality DuoZhong factors by the things, make a can be reasonably comprehensive these attributes or the overall evaluation factors )

根据对真空蒸发镀膜的分析，在40×40的范围内分别蒸 发：1000、5000、10000、20000、30000个粒子。  利用2维数组记录每个点的粒子数。  初始粒的横纵坐标为0～40的均匀分布。  能量为（15，3）的正态分布。  在基体表面自由行走时损失1的能量。  若该点有粒子，即与其他粒子相遇时损失3的能量。  由低处向高处扩散，每扩散一层，损失4的能量，由高处 向低处扩散，损失3的能量。  当粒子的能量小于等于0时停留下来，该点的粒子数加1。  临界核的尺寸为10个粒子。  根据每个点粒子个数的不同，以不同的灰度显示这些点。 点越亮，则表示该点的膜越厚。  以图形方式显示粒子初始能量的正态分布情况(Based on the analysis of the vacuum evaporation coating, respectively, in the range of from 4040 evaporated: 1000,5000,10000,20000,30000 particles.  each point using 2-dimensional array to record the number of particles. The  initial grains transverse and longitudinal coordinates of a uniform distribution of 0 to 40. The  energy as a normal distribution (15,3).  1 energy losses in the substrate surface to walk.  point particles that 3 energy loss in the encounter with the other particles.  by the lower diffusion tops every diffusion layer, a loss of 4 energy diffusion from high to low, the energy loss of 3.  When the energy of the particles is less than or equal to 0:00 stay down, add 1 to the number of particles that point.  critical nucleus size of 10 particles.  these points, depending on the number of particles of each point is displayed in a different shade. Point, the brighter, the thicker the point of the fi)