-
dtc2014
limitation of load angle in pmsm
- 2015-04-12 18:49:48下载
- 积分:1
-
cyclic_AR
信号处理,振动方面的,很有用,绝不后悔,帮助很大(Signal processing, vibration issues, useful, never regret, very helpful)
- 2014-02-13 11:46:42下载
- 积分:1
-
完整的基于压缩感知中DCT基的BP算法源代码
复化三点Gauss-lengend公式求pi,包括 MUSIC算法,ESPRIT算法 ROOT-MUSIC算法,抑制载波型差分相位调制,利用贝叶斯原理估计混合logit模型的参数,利用matlab GUI实现的串口编程例子,计算加权加速度。
- 2022-02-03 23:47:21下载
- 积分:1
-
20100203
说明: 用matlab语言实现的将图像的进行dpcm编码算法,之后进行图像重构,进行前后图像的对比。(With matlab language will be dpcm image coding algorithm, after the image reconstruction, the images before and after contrast.
)
- 2011-03-25 10:30:18下载
- 积分:1
-
cc
说明: 改进神经元自适应的pid控制,采用本算法,全系数的在线修正就不完全是根据神经网络学习原理,而是参考实际经验制定的(Improve the neuron adaptive pid control, the use of the algorithm, the coefficient of online correction is not completely according to the principle of neural network learning, but refer to the practical experience)
- 2014-08-21 20:15:05下载
- 积分:1
-
FDTD3D
FDTD _ 3D code in matlab
main structure of 3D fdtd code
- 2013-07-21 23:06:58下载
- 积分:1
-
Hamiltion
程序理论详见内附的pdf:《Hamilton图的充要条件及圈的矩阵算法》
主程序为
[K]=getPk(A,k)
A表示图的邻接矩阵,k表示k阶长路和圈
返回K表示该图的所有k阶长路和圈
其他函数介绍:
Ppro定义路的乘法
Psum定义路的加法
MatPro定义路矩阵的乘法
isaPorC判断是否为路或圈
P2subP提取路的和式中的所有路
getP1从邻接矩阵得到1阶路矩阵(get a k-path from a graph)
- 2014-09-13 07:05:38下载
- 积分:1
-
2332
【matlab编程代做】水平集模型的图像分割 ([Do] matlab programming generation level set image segmentation model)
- 2015-01-20 21:30:16下载
- 积分:1
-
A-duffing
说明: 用于检测微弱信号的Duffing系统,这是我的毕业设计一部分,因为我做的时候也曾求取过很多资料,但是并没有找到,因此在我完成之后,上传这个代码,希望这个能帮助别人。
里面还有后续做的GUI界面实现的Duffing振子检测功能,可检测信号幅值和频率。(The Duffing system for detecting weak signals, this is part of my graduation project, because I also asked for a lot of information when I did it, but it was not found, so after I finished, upload this code, I hope this can help others.)
- 2019-06-08 20:47:42下载
- 积分:1
-
SQP
基于active-set 的SQP算法,用于求解非线性不等约束(SQP algorithm used to find a constrained minimum of a function of several variables based on active-set algorithm, subject to the nonlinear inequalities.)
- 2011-05-25 12:50:59下载
- 积分:1