C语言写的Hash算法，在各种平台上都编译通过，可以直接使用。...

本书是作者编程经验的结晶，由发表在杂志上的专栏文章构成，每一章内容相对独立，但都是编程过程中的有机组成部分。本书内容包括问题定义、算法、数据结构、程序验证与测试、程序优化与效率问题，以及这些技巧在排序、查找和字符串处理等方面的几个实际应用。本书每章末尾都附带有相关内容的问题，附录中给出了一些问题的提示和解答。仔细思考问题或与同事进行讨论，可以巩固所学知识，将作者的经验应用到自己的编程实践中。-This book is the author of the crystallization of programming experience, published in the journal by the column consists of the contents of each chapter is relatively independent, but they are in the process of programming an integral part. The book includes problem definition, algorithms, data structures, program verification and testing, process optimization and efficiency issues, as well as these skills in sorting, string search and deal with several aspects of practical application. The book comes at the end of each chapter has relevant content issues, the appendix gives some tips and answers to the problem. Think carefully about questions or discussion with colleagues, you can consolidate the knowledge acquired will be applied to the author

给售房作的,但还没有全完成,最好是只看看里面有用的东东就可以了-售房to make, but has not yet completed the whole, it is best just to see if there can be a useful Dongdong the

n后问题,实现n后问题的求解,并且可以输出最有解-n, n after realizing the problem solving, and can export most Solution

考试管理程序，属数据库管理类，直接解压后就可以使用。-examination management processes, database management is a category that can be directly extracted after use.

树结构之线索话二叉树，二叉树的存储结构，线索二叉树的构造。中序线索化，递归算法，非递归算法。

java客房管理系统-java客房管理系统！！！！！！！！！！

皇后算法111 很经典的 内含两种 希望大家喜欢-111 Queen"s algorithm includes the classic two hope you like

插值类 CInterpolate 一元全区间不等距插值 一元全区间等距插值 一元三点不等距插值 连分式不等距插值 埃尔米特不等距插值 光滑不等距插值 二元全区间插值-interpolation category CInterpolate one yuan is not equidistant between the region interpolation one yuan region equidistant between 3:00 interpolation one yuan is not even fractional offset interpolation is not equidistant interpolation Hermite"s not equidistant interpolation smooth interpolation is not equidistant between two yuan region Interpolation

pc游戏编程_人机博弈,算法和实现都比较完整，源码可运行。且可以从中学到很好的算法知识，和人机博弈-pc game programming _ man-machine game, algorithms and realization are relatively complete, source code can run. And can learn a good knowledge of algorithms, and human-computer game

天长地久一般现有21场比赛，两人轮换，每人可从1场拿下4场，不可多拿。我们也不能得到，谁拿了最后的红火谁输了比赛。请编写一个人机游戏的程序，先向电脑索取并取得“一台电脑要‘长生不老将军’”*分析和设计算法后在电脑上取情况，才能使电脑成为‘长生不老将军’必须从中找出关键。按照这个题目的要求来总结自己的想法，以后取一个为数的孩子与对方只需一步和数额相等，最后我们就可以保证给孩子留下一个长子这是个人的。相应的分析算法