opencv 人脸识别代码

一个图片浏览器,功能不算强-a picture browser, function is not strong

全书介绍了图像科学综述、MATLAB语言图像编程、图像增强等内容,涵盖了医学图像处理等应用实例,并结合理论算法,提供了大量MATLAB代码程序,以帮助读者掌握如何使用MATLAB语言快速进行算法的仿真、调试和估计等方法。 -ImageProcessing and Recognition of Practical Case Highlights

有关图形编程方面的VC源码，相信大家会用得上的-the graphical programming of VC source, I believe we need them!

spineline object 3d rotation viewer

基于vtk的三维重构与裁切: 1.16位非压缩位图的读取与设置. 2.图像数据载入映射器 3.裁切平面的设置 4.边界的设置与显示 5.三维重构 注:需安装vtk4.0以上版本-It s about 3D reconstruct and clip based on VTK including reading and configration of 16 bits non_contracted bitmaps,the mapper for image data loading, configration of plane for clip,configration and display of borders and 3D reconstruct.(PS:VTK 4.0 or above version is needed)

图像，边缘检测方面的源码，进行微分处理运算，速度较快-Images, edge detection of the source area to carry out differential processing algorithms, faster

-用C语言画分形图 -- Use of C language painting fractals

该程序时用VC++6.0实现的，对灰度图像来进行膨胀和复试以及开闭运算，对学者应该有帮助。-When the program is implemented with VC++6.0 on the grayscale image to carry out expansion and re-testing, as well as opening and closing operation, pairs of scholars should be helpful.

用VC6.0写的一个数字图像处理小软件，用于课程设计-VC6.0 to write with a small digital image processing software for curriculum design

现图形学中画直线，园和圆弧以及直线裁剪，区域填充等功能 1． 对于画直线，只需知道起点和终点即可。在工作区间中按下鼠标（即选择起点），拖动至另一处松开（终点），即得到直线。 2． 画圆需要圆心坐标、半径、及起始角和终止角，至于实验要求的画1/4圆弧，可设起始角=0，终止角=45，若要画整个圆弧起始角和终止角分别为0和360即可。-Graphics are painting a straight line, arc, as well as garden and cut a straight line, filled with features such as region 1. For painting a straight line, just know that you can start and finish. Interval in the work of the mouse click (that is, to choose the starting point), drag to another release (the end), that is to be a straight line. 2. Drawcircle need to center coordinates, radius, and the termination of the initial angle and angle, as required by experimental painting 1/4 arc, the starting angle can be set = 0, terminate the angle = 45, in order to draw the whole arc start angle and termination angle is 0 and 360, respectively, can be.