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Kruscal algorythm
这是kruskal算法,用于计算图中的最小展开式3。它是用java编程的,包含一个使用javaswing技术的GUI。
- 2022-02-12 03:06:08下载
- 积分:1
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这个傅立叶实例算法使用了基2、基3、基4、基5、基8、基10……混合算法,几乎可以计算任意长度的FFT。说明白点也就是当序列长度n为2、3、5、7、11等这些比...
这个傅立叶实例算法使用了基2、基3、基4、基5、基8、基10……混合算法,几乎可以计算任意长度的FFT。说明白点也就是当序列长度n为2、3、5、7、11等这些比较小的素数时,或者n的最大素因数
- 2022-11-15 09:35:04下载
- 积分:1
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寻最短路径算法
一个模拟游戏中最短路径的算法
从一个点,到另一个点的最短路径,中间可以设置障碍
看是如果绕过障碍获得最短路径
- 2022-12-09 16:30:03下载
- 积分:1
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immune algorithm 求解 tsp问题 python
immune algorithm 求解 tsp问题 python
- 2022-10-10 05:55:03下载
- 积分:1
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asdfdsadfsdfsdaaaaaaa
dddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
- 2022-11-05 00:35:05下载
- 积分:1
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C语言作的四色验证1.需求分析问题描述:证明了可以用不多于4种颜色对n个区域着色,而满足相邻的区域具有不同的颜色输入形式 : 暂定最多50个区域,如需证明更多区...
C语言作的四色验证1.需求分析问题描述:证明了可以用不多于4种颜色对n个区域着色,而满足相邻的区域具有不同的颜色输入形式 : 暂定最多50个区域,如需证明更多区域,修改#define S 50 即可;以整形形式输入(取值范围1-32767)用户需要证明的区域数目,相联的一对矩阵; 输出形式:以0和1输出关联矩阵,和以blue yellow orange pink形式输出每个区域相对应证明出的颜色;-C language does four colors confirm 1. demands analyses
question description: Had proven may use not to be many to 4 kind of
colors to n region coloration, but satisfies the neighboring region to
have the different color input form: Establishes provisionally more
than 50 regions, if must prove more regions, revise#define S 50 then;
Region number (value scope 1-32767) the user needs to prove which by
the reshaping form input, unites a pair of matrix; Output form: By 0
and 1 output incidence matrixs, with form outputs the color by blue
yellow orange the pink which each region corresponds proves;
- 2022-10-20 02:35:04下载
- 积分:1
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Vondrak算法:主要用于未知函数测量数据滤波
Vondrak算法:主要用于未知函数测量数据滤波-Vondrak algorithm: being used in the filtering of measuring data whose function is unknown.
- 2022-02-07 20:14:03下载
- 积分:1
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code for FDTD 1D with pml and source
code for FDTD 1D with pml and source
- 2022-01-31 17:41:44下载
- 积分:1
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先由原始图像(任选)产生待恢复的图像;(产生方法如下:冲激
函数为 ,将原始图像与冲激函
数卷积产生模糊,然后再迭加均值为0,方差为8,16,32的
先由原始图像(任选)产生待恢复的图像;(产生方法如下:冲激
函数为 ,将原始图像与冲激函
数卷积产生模糊,然后再迭加均值为0,方差为8,16,32的高斯
随机噪声而得到一组待恢复的图像 ;
-By the original images (optional) have to be the restoration of the image (the method is as follows: impulse function, the original image with the impulse function arising convolution fuzzy, and then stacking the mean is 0, the variance for the 8,16 , 32 the Gaussian random noise has been a group of images to be restored
- 2022-10-15 12:35:03下载
- 积分:1
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Fortran求解矩阵线性方程组,有例子,可以直接运行
Fortran求解矩阵线性方程组,有例子,可以直接运行
/"P.S:本软件既可以计算线性方程组Ax=b,也可以计算矩阵方程AX=B")
Purpose : 消去法解矩阵方程
!
!-----------------------------------------------------
! In put data files :
! 1. fin.txt 输入方程系数
! 2.
! Output data files :
- 2023-03-15 08:45:04下载
- 积分:1