-
Have you ever wanted to copy a file from your Desktop Computer to your handheld...
Have you ever wanted to copy a file from your Desktop Computer to your handheld Pocket PC? This included any Windows CE version too? Well if so, I will present an easy way to do it here: It s called the Remote Application Programming Interface, or, RAPI in this article. It is touched on in the MSDN but not really explained very well.
- 2022-05-08 05:38:52下载
- 积分:1
-
皮肤操作的DEMO,很简单的,不是那么高级的,但是有帮助的。
皮肤操作的DEMO,很简单的,不是那么高级的,但是有帮助的。-Skin operation DEMO, is very simple and not so advanced, but there is help.
- 2022-04-22 08:11:18下载
- 积分:1
-
弹珠台游戏,呵呵不知道对你们有用吗,有用就下载吧,呵呵,看看好不好、...
弹珠台游戏,呵呵不知道对你们有用吗,有用就下载吧,呵呵,看看好不好、-Pinball games, Oh do not know any use to you, useful to download it, huh, huh, good to see,
- 2022-02-15 16:04:21下载
- 积分:1
-
取硬盘ID,DLL版
取硬盘ID,DLL版-drive from ID, DLL version
- 2023-07-07 07:05:03下载
- 积分:1
-
一个简易日历程序,已知公元元年一月一日即耶稣诞生日是星期一,那么因为365%7=1,366%7=2。所以每过一年平年星期数加一,每过一年闰年星期数加二,依次类推...
一个简易日历程序,已知公元元年一月一日即耶稣诞生日是星期一,那么因为365%7=1,366%7=2。所以每过一年平年星期数加一,每过一年闰年星期数加二,依次类推就可以求出任意一年一月一日是星期几。-a simple calendar program, known Year on January 1 that the first year of the birth of Jesus Day is Monday, because 365% = 1,366 7% 7 = 2. So every non-leap year over year increase in a few weeks, a leap year every year the number increases two weeks, followed by analogy can be found arbitrary January 1, 2001 is several weeks.
- 2022-02-04 23:46:52下载
- 积分:1
-
dos上的中文菜单程序,用C++编写。希望能给大家有一定的参考价值。...
dos上的中文菜单程序,用C++编写。希望能给大家有一定的参考价值。-dos on the Chinese menu procedures, using C++ prepared. I hope everyone can have a certain reference value.
- 2023-07-21 00:10:03下载
- 积分:1
-
对java代码第二十八所,很经典的哟,包括所有方面…
28日学会Java的代码,内容很经典的哟,包括Java的方方面面,-Institute on the 28th of Java code, as is the classic yo, including all aspects of Java.
- 2022-03-01 03:02:09下载
- 积分:1
-
简单计算器软件的设计,能够实现科学计算与标准界面。
简单计算器软件的设计,能够实现科学计算与标准界面。-Simple calculator software design, scientific computing can be achieved with the standard interface.
- 2022-06-12 08:07:09下载
- 积分:1
-
约瑟夫斯写的问题解决功能。用整数序列的1,2,3…
编写一个求解Josephus问题的函数。用整数序列1, 2, 3, ……, n表示顺序围坐在圆桌周围的人。然后使用n = 9, s = 1, m = 5,以及n = 9, s = 1, m = 0,或者n = 9, s = 1, m = 10作为输入数据,检查你的程序的正 确性和健壮性。最后分析所完成算法的时间复杂度。定义JosephusCircle类,其中含完成初始化、报数出圈成 员函数、输出显示等方法。-Josephus write a problem solving function. With the sequence of integers 1, 2, 3, ... ..., n the order of sitting around the round table, said the people around. And then use n = 9, s = 1, m = 5, and n = 9, s = 1, m = 0, or n = 9, s = 1, m = 10 as input data, check the correctness of your program and robustness. Completed the final analysis, the algorithm" s time complexity. Definition JosephusCircle class, which included the completion of initialization, reported that the number of member functions of a circle, the output display and other methods.
- 2022-12-02 00:35:03下载
- 积分:1
-
Win32系统服务:对CD 95和Windows NT的例子窗心
Win32系统服务:windows95和windowsnt的核心示例,附光盘一本。这方面的经典著作,只有出版时间较长,反而具有一定的参考价值
- 2022-09-16 03:55:03下载
- 积分:1