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Bridge design pattern in a routine mode of C++ Prepared to read the code to unde...
设计模式中桥模式的一个例程
C++编写
看了代码对理解桥模式有很大帮助-Bridge design pattern in a routine mode of C++ Prepared to read the code to understand the bridge model are very helpful
- 2022-02-20 09:11:21下载
- 积分:1
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C#Winform里的扩展Tab控件
资源描述Winform里的重写、Tab控件扩展,使用自定义TabControl实现,鼠标悬停时图标变成绿色
可以改变面板的大小。需要学习控件制作的可以下载学习。
实现方法:
用System.Threading.Timer加上一个简单的委托异步修改面板大小来实现动画
鼠标悬停时图标变成绿色是判断鼠标划过哪个标签是通过对MouseMove鼠标移动实时采点来实现的
- 2022-02-02 16:02:47下载
- 积分:1
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这是有关2进制数的算法
这是有关2进制数的算法-This the number of two-band algorithm
- 2022-03-17 21:29:37下载
- 积分:1
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i want to something in this intnet that i need it very much!
i want to somethin...
tlc549 AD转换程序
i want to something in this intnet that i need it very much!-i want to something in this intnet that i need it very much!
i want to something in this intnet that i need it very much!
- 2022-02-26 21:27:36下载
- 积分:1
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通过GPRS modem 计算机串口相连,实现GPRS的短线收发和数据传输!...
通过GPRS modem 计算机串口相连,实现GPRS的短线收发和数据传输!-GPRS modem through the serial port connected to the computer to achieve the short-term GPRS transceiver and data transmission!
- 2022-12-19 04:15:03下载
- 积分:1
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用。net编写的C++程序,写一个对沉降的超市销售…
用.net编写的C++程序,写一个超市的售货结算,手动输入模拟读码器。-used. Net prepared by the C program, write a supermarket for the sale of settlement, manual input simulation code reading device.
- 2022-06-29 02:51:30下载
- 积分:1
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计算机组态软件编程教材的源代码,虽然书写得不怎么样,但是这些小程序对大家还是很有帮助的。第一章...
计算机组态软件编程教材的源代码,虽然书写得不怎么样,但是这些小程序对大家还是很有帮助的。第一章-Teaching computer programming configuration software source code, although not how to write, but the U.S. is still a small program useful. Chapter I
- 2022-04-17 19:11:23下载
- 积分:1
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人体追踪 驱动串口
基于nite2的人体追踪,通过nite获得人体编号,然后获取对应骨骼坐标,再转换成世界坐标,并设定再一定范围内,电机不动,否则向对应的方向运动,从而实现对人体的跟随功能。
- 2022-08-24 07:04:20下载
- 积分:1
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动态链接库d
动态链接库d-dll,dllllllllllllllllllllllllllllllll
- 2022-01-26 04:23:37下载
- 积分:1
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分析:用N进制的方法吧。设一个N个单元的数组,对第一个单元做加一操作,满N进
一。每加一次一就判断一下各位数组单元有无重复,有则再转回去做加一操作,没有则...
分析:用N进制的方法吧。设一个N个单元的数组,对第一个单元做加一操作,满N进
一。每加一次一就判断一下各位数组单元有无重复,有则再转回去做加一操作,没有则说明得到了一个排列方案。
-Analysis: N-band approach with it. A N-unit array, and add a unit to do one operation, over N into one. Add 1 each time you click on an array of modules to determine whether or not duplicate, then go back and have to do is add one operation, then there is no order to be a program.
- 2022-06-20 13:07:53下载
- 积分:1