没什么特别的 用ASSECC数据库~――~

题目：有1、2、3、4个数字，能组成多少个互不相同且无重复数字的三位数？都是多少？ 1.程序分析：可填在百位、十位、个位的数字都是1、2、3、4。组成所有的排列后再去掉不满足条件的排列。 2.程序源代码：-topic : 1,2,3,4 figures, the number can be formed with each other with no repeat of the triple-digit figures? How many are? 1. Program Analysis : can fill the 100, 10, 000 the number of spaces are 1,2,3,4. With all the components removed after not satisfied with the conditions. 2. Source code :

《数据结构》算法实现与解析-"data structure" and parsing algorithm

八 方块移动游戏要求从一个含8个数字（用1-8表示）的方块以及一个空格方块（用0表示）的3x3矩阵的起始状态开始，不断移动该空格方块以使其和相邻的方 块互换，直至达到所定义的目标状态。空格方块在中间位置时有上、下、左、右4个方向可移动，在四个角落上有2个方向可移动，在其他位置上有3个方向可移 动。例如，假设一个3x3矩阵的初始状态为： 8 0 3 2 1 4 7 6 5 目标状态为： 1 2 3 8 0 4 7 6 5-Eight-box requirements of mobile games from one containing eight numbers (1-8 with express) the box, as well as a space box (with 0) of the 3x3 matrix of the initial start, and constantly move the box to make space its adjacent box and swap until they reach their defined target state. Spaces in the middle position box has the upper and lower, left and right direction of four removable, in the four corners there are two directions can be mobile, in other locations has three movable direction. For example, suppose a 3x3 matrix of the initial state as follows: 803,214,765 target state as follows: 123,804,765

递归算法，字符串的倒序输出。-recursive algorithm, the reverse output string.

该软件可以制作百威收银系统全系列的购物券单个生成和批量生成，生成数据为随机数据

建立带表头结点的单链表，打印所有结点的数据域；输入一个值，若某个结点的数据域为该值，则在其后插入另一个新结点，若无此结点，则在表尾插入新结点，然后打印；给一个值，删除结点的数据域是该值的所有结点，然后打印。（表生成时可用前插法或后插法）-table with the establishment of the first node of a single linked list, print all nodes of the data domain; An input value, If a node"s data fields for the values, and subsequently inserted in a new node, in the absence of such nodes, at the end of the insertion of a new form nodes, then Print; to a value of the node to delete data domain is the value of all the nodes, then Print. (Table Generation available houses or after interpolation)

回文游戏，c语言，有源码，可以参考研究使用。-palindrome games, c language, and the source code can reference study.

asp人事管理系统，可以用于毕业设计。供大家学习-asp Personnel Management System, can be used for graduation design. For them to learn from

使用VC编写的栈的链式表示和实现程序，简单明了，方便使用-Prepared using the VC stack chain expression and realization of program, simple and clear, easy to use

如果车不动，请算法设计：乘日本马但车不能吃，设计回溯用马走，并打印出距离。可作为设计软件的参考