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c++实现模拟内存管理
本程序由C++实现内存管理,主要有新建进程和结束进程两个功能,这两个功能又通过链表的基本操作来完成,增加、删除结点,还有排序。
- 2022-08-11 00:30:27下载
- 积分:1
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“数据结构、算法和程序”这个抽象世界的特殊旅程,以解决现实生活中的许多难题...
“数据结构、算法和程序”这个抽象世界的特殊旅程,以解决现实生活中的许多难题- Data structures, algorithms and procedures of the abstract world of a special journey to solve many real-life problems
- 2023-03-03 18:00:06下载
- 积分:1
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顺序表的基本操作
顺序表的基本操作-order the basic operation
- 2022-02-03 07:21:59下载
- 积分:1
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本人上传的是用贪心算法实现找零钱问题。贪婪算法的根本思想是逐步获得最优解。...
本人上传的是用贪心算法实现找零钱问题。贪婪算法的根本思想是逐步获得最优解。-I uploaded is to use greedy algorithm to find small change problem. Greedy algorithm is the fundamental idea is to gradually get the optimal solution.
- 2022-03-02 15:39:29下载
- 积分:1
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Prim 算法寻找最小生成树,用C语言实现,有完整的注释!
Prim 算法寻找最小生成树,用C语言实现,有完整的注释!-Prim algorithm to find the minimum spanning tree, using C language, a complete Notes!
- 2022-03-02 08:32:59下载
- 积分:1
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这是同学信息资料管理系统的设计,包括设计说明!
这是同学信息资料管理系统的设计,包括设计说明!-This is a classmates information manager design including design specification.
- 2022-07-02 06:57:44下载
- 积分:1
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NetBeans under the Java access to the database project file.
NetBeans下的 Java访问数据库的工程文件。-NetBeans under the Java access to the database project file.
- 2022-04-24 23:51:14下载
- 积分:1
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一个解码的类,常用在条形码的解码中,是老外写的比较实用...
一个解码的类,常用在条形码的解码中,是老外写的比较实用-a decoder category, commonly used in bar code decoding, the foreigner is more practical writing
- 2022-01-25 19:50:48下载
- 积分:1
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线性代数中的矩阵求逆的问题,使用此算法可以简化矩阵的操作。...
线性代数中的矩阵求逆的问题,使用此算法可以简化矩阵的操作。-linear algebra of matrix inversion, the use of this algorithm can be simplified matrix operation.
- 2022-03-11 00:15:52下载
- 积分:1
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/* Maze * Starting point is m[0][0], need to find a path go to m[9][9]. 0 means...
迷宫算法(maze)
/* Maze * Starting point is m[0][0], need to find a path go to m[9][9]. 0 means OK,
* 1 means cannot go there, boundary is 0 and 9, cannot go beyond boundary.
* Each step can be made horizontally or vertically for one more grid (diagonal
* jump is not allowed).
* Your program should print a series of grid coordinates that start from m[0][0]
* and go to m[9][9]
* Hint: No need to find the shortest path, only need to find one path that gets
* you to desitination.
*/
-/* Maze * Starting point is m[0][0], need to find a path go to m[9][9]. 0 means OK,
* 1 means cannot go there, boundary is 0 and 9, cannot go beyond boundary.
* Each step can be made horizontally or vertically for one more grid (diagonal
* jump is not allowed).
* Your program should print a series of grid coordinates that start from m[0][0]
* and go to m[9][9]
* Hint: No need to find the shortest path, only need to find one path that gets
* you to desitination.
- 2022-08-08 06:28:42下载
- 积分:1