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hotel reservation systems to provide housing and the number of beds allocated fo...
旅馆订位系统 提供住房及床位分配功能并且能进行退房处理-hotel reservation systems to provide housing and the number of beds allocated for functional and can handle Checkout
- 2022-04-11 03:29:39下载
- 积分:1
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KS0108液晶显示控制器。
for ks0108 LCD Controller
- 2023-03-30 05:00:03下载
- 积分:1
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fft c源程序,希望可以和大家交流
fft c源程序,希望可以和大家交流-fft source, and we can hope that the exchanges
- 2022-01-25 18:57:43下载
- 积分:1
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服务器代码3.5。这8款
服务端代码 3.5的在。... ... .....
-server code in 3.5. That clause 8
- 2022-03-18 14:05:34下载
- 积分:1
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A string of hexadecimal for summary (including md5 and sha
一款将十六进制串进行摘要(包括md5和sha-1),非常好用。-A string of hexadecimal for summary (including md5 and sha-1), very handy.
- 2023-04-02 13:50:03下载
- 积分:1
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软件工程的设计和开发文件,由于本人也不知道怎么回事,所以还请读者自己去斟酌,希望对你们有帮助!...
软件工程的设计和开发文件,由于本人也不知道怎么回事,所以还请读者自己去斟酌,希望对你们有帮助!-software engineering design and development, because I do not know how, therefore, also invited readers to their own discretion, and I hope to have your help!
- 2022-07-22 23:19:42下载
- 积分:1
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mainboard BIOS upgrade tool, more suitable for the use of the old machines! Anot...
主板BIOS升级工具,适合较古老的机器使用!
另一版本8.26版-mainboard BIOS upgrade tool, more suitable for the use of the old machines! Another version of version 8.26
- 2022-08-13 09:07:29下载
- 积分:1
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labview教材的配书课件。制作详细,可供参考。共6部分,下载后统一解压...
labview教材的配书课件。制作详细,可供参考。共6部分,下载后统一解压-LabVIEW courseware materials with the book. The production of detailed, for reference. A total of 6 parts, download decompression unification
- 2022-01-25 15:20:12下载
- 积分:1
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WINDOWS above classic game. To cell phone, very well, we can try
WINDOWS上面经典的游戏。转到手机上面的,很不错,大家可以-WINDOWS above classic game. To cell phone, very well, we can try
- 2022-01-31 11:49:43下载
- 积分:1
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数根
数也有根吗?有!数根就是把一个数的各个数位上的值相加,直到得到一个一位数为止。请你编写一个程序来计算任意数N(0≤N≤1000000000000)的...
数根
数也有根吗?有!数根就是把一个数的各个数位上的值相加,直到得到一个一位数为止。请你编写一个程序来计算任意数N(0≤N≤1000000000000)的根。
输入:
输入有多个案例。每一个案例为一行,每行只有一个整数N。当输入的N是-1时,输入结束。
输出:
每一个案例输出一行。每行只有一个数字,就是N对应的数根。
Sample input
39
-1
Sample output
3-Number of root number also has roots do? There is! The number of roots is to a number of different values on the digital sum until they have been a number of up to one. Please write a program to calculate an arbitrary number N (0 ≤ N ≤ 1000000000000) roots. Input: Enter a number of cases. Each case for the line, each line is only an integer N. When the input of N is-1, the input end. Output: the output line of each case. There is only one number per line, that is, N corresponds to the number of roots. Sample input 39-1 Sample output 3
- 2023-09-05 21:25:03下载
- 积分:1