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二
根据二维空间内目标作匀速直线运动和匀速圆周运动的特点,在建立目标运动模型和观测模型的基础上采用基于交互多模算法(IMM)的卡尔曼滤波器对机动目标进行跟踪。仿真结果表明,该算法不仅能够对匀速直线运动和匀速圆周运动的目标进行跟踪,而且在运动模型发生变化时,滤波误差也比较小。
关键词:卡尔曼滤波器;目标跟踪;机动;交互多模(IMM)
-two-dimensional space under target for uniform linear motion and uniform circular motion characteristics, the establishment of the target model and observations on the basis of the model based on interactive multi-algorithm (IMM) Kalman Filter right track moving targets. Simulation results show that the method can not only on uniform linear movement and the uniform circular motion of the target tracking, and the campaign model change, the filter error is relatively small. Keywords : Kalman filter; Target tracking; Mobility; Interactive multi-mode (IMM)
- 2022-02-11 17:57:23下载
- 积分:1
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n皇后问题的C++实现
n皇后问题的C++实现-n Queen"s realization of C
- 2022-07-15 11:06:40下载
- 积分:1
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设计模式中 代理模式和工厂模式的C++实现
关于设计模式的问题在IT面试时越来越多的被问到,该源码实现了代理模式和工厂模式,其中代理模式在main函数中被注释掉了,当前运行的是工厂模式,如果想了解代理模式,将注释去掉即可。
- 2023-03-09 19:10:03下载
- 积分:1
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电脑维修技术,为千千万万PC用户解决生活中遇到的各种故障和疑难杂症
电脑维修技术,为千千万万PC用户解决生活中遇到的各种故障和疑难杂症-Computer maintenance technology, for tens of thousands of PC users to solve a variety of life encountered failure and incurable diseases
- 2022-08-17 14:25:34下载
- 积分:1
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caculater
多功能计算器能够实现基本计算器的功能,此文件为参考代码,详情请下载之后再查看。-caculater
- 2022-01-28 05:28:02下载
- 积分:1
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FPGA of some basic conceptual issues back, has great help for beginners.
FPGA的一些基本概念问题回复,对初学者有很大帮助。-FPGA of some basic conceptual issues back, has great help for beginners.
- 2022-03-02 01:18:27下载
- 积分:1
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内存管理
memory management
- 2022-07-10 03:27:20下载
- 积分:1
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数根
数也有根吗?有!数根就是把一个数的各个数位上的值相加,直到得到一个一位数为止。请你编写一个程序来计算任意数N(0≤N≤1000000000000)的...
数根
数也有根吗?有!数根就是把一个数的各个数位上的值相加,直到得到一个一位数为止。请你编写一个程序来计算任意数N(0≤N≤1000000000000)的根。
输入:
输入有多个案例。每一个案例为一行,每行只有一个整数N。当输入的N是-1时,输入结束。
输出:
每一个案例输出一行。每行只有一个数字,就是N对应的数根。
Sample input
39
-1
Sample output
3-Number of root number also has roots do? There is! The number of roots is to a number of different values on the digital sum until they have been a number of up to one. Please write a program to calculate an arbitrary number N (0 ≤ N ≤ 1000000000000) roots. Input: Enter a number of cases. Each case for the line, each line is only an integer N. When the input of N is-1, the input end. Output: the output line of each case. There is only one number per line, that is, N corresponds to the number of roots. Sample input 39-1 Sample output 3
- 2023-09-05 21:25:03下载
- 积分:1
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avr串口开发,计算串口的数据,及开发的代码
avr串口开发,计算串口的数据,及开发的代码-avr development, the calculation of serial data, and the development of the code
- 2023-08-27 20:05:04下载
- 积分:1
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Introduction to Algorithms MIT course lecture notes, very complete, is a compute...
MIT算法导论课程的讲义,十分齐全,是计算机专业的学生学习算法设计的经典入门材料-Introduction to Algorithms MIT course lecture notes, very complete, is a computer science students to learn the classic algorithm design entry materials
- 2022-08-08 10:27:05下载
- 积分:1