acm大赛题，

C++部分知识点，反正是好东东，看啦就知道，我友情提供，-knowledge, because it is good Dongdong, Kanla know, I provide friendship, huh

Visual C++6_0数据库系统开发实例导航 提供给开发数据库的朋友们，共同进步，-Visual C 6_0 database systems development to provide examples of the development of navigation database friends, common progress, thank you

vc mfc 编程实例 如何创建一个窗口、销毁一个窗口和控制windows操作系统与窗口的通信问题-vc mfc programming examples of how to create a window to destroy a window and control window of the windows operating system and communication problems

一个关于图形图向生成的软件-on a graphical map generation software

c++课程习题集的源代码，初学者的好帮手，请尊重作者的劳动。-c++ courses Exercises Set source code, for beginners a good helper, please respect the author

matlab7.0应用编程，中文资料，每章一个文件-Application Programming matlab7.0, English information, each devoted to a file

PCI接口规范中文版说明,初次接触PCI开发的好帮手。-PCI interface specification Chinese version of that initial contact PCI"s good helper.

zemax源码： This DLL models an anamorphic aspheric surface. This surface is essentially an even aspheric surface with different terms for the x and y directions. The sag is given by: Z = ((CX*x*x)+(CY*y*y)) / (1 + sqrt(1-((1+KX)*CX*CX*x*x)-((1+KY)*CY*CY*y*y))) + AR*( (1 - AP)*x*x + (1 + AP)*y*y )^2 + BR*( (1 - BP)*x*x + (1 + BP)*y*y )^3 + CR*( (1 - CP)*x*x + (1 + CP)*y*y )^4 + DR*( (1 - DP)*x*x + (1 + DP)*y*y )^5 Note the terms AR, BR, CR, and DR ... have units of length to the -3, -5, -7, and -9 power. The terms AP, BP, CP, and DP are dimensionless. The surface is rotationally symmetric only if AP = BP = CP = DP == 0 and CX = CY and KX = KY. -ZEMAX source: This DLL models an anamorphic aspheric surface.This surface is essentially an even aspheric surface with different terms forthe x and y directions.The sag is given by: Z = ((CX* x* x)+ (CY* y* y))/(1+ sqrt (1- ((1+ KX)* CX* CX* x* x)- ((1+ KY)* CY* CY* y* y)))+ AR* ((1- AP)* x* x+ (1+ AP)*

SERVLET编程，一本很不错的书

.net性能优化中文说明- net performance optimization Chinese showed