USACO Section 2.1的全部AC的代码 OIer专用.

有一个打印机被不同类型的用户共享，当某个用户使用其时，必须先检测其它用户是否在使用，假设函数inuse（）当有用户使用打印机时返回1，当没有用户使用时返回0。把函数inuse（）作为不同类的友元函数，请设计。-a printer by different types of users to share, when a user to use their time and must first detect whether other users in the use of the assumption that inuse function () when users return to a printer. When users do not use return 0. Inuse put function (), as different types of Friends yuan function, design.

pipe类 pipe类 -pipe-type pipe-type pipe-type pipe-type

支撑向量机训练算法研究，很好的参考资料，有兴趣的可以下载-Support vector machine training algorithm research, a good reference, are interested in can be downloaded

编号为1-52张牌，正面向上，从第2张开始，以2为基数，是2的倍数的牌翻一次，直到最后一张牌；然后，从第3张开始，以3为基数，是3的倍数的牌翻一次，直到最后一张牌；然后…从第4张开始，以4为基数，是4的倍数的牌翻一次， 直到最后一张牌；...再依次5的倍数的牌翻一次，6的，7的 直到 以52为基数的 翻过，输出：这时正面向上的牌有哪些？-No. 1-52 card in a positive, progressive, from the first two, with two as the base, 2 is a multiple of the license over time, until finally a license; Then, from the first three starting with three to the base, 3 is a multiple of the license over time, until finally a license; Then ... from the first four starting to four as the base, 4 is a multiple of the license over time, until finally a license; ... followed by the five multiples of the licensing repotted once, 6, 7 to 52 until the base of the turn, the output : At this time positive signs of upward What?

著名游戏贪吃蛇用vc开发出来的，大家帮忙给点意见，这是我第一次程序-famous game Snake vc developed with the help of everyone to the point, this is my first procedure

使用ArcEngine java api开发的，打开一个shape文件，并显示其中所有记录的值-ArcEngine java api use development, open a shape file, and display all records in which the value of

一个经典的贪吃蛇游戏,难免有点缺陷,请大家指出来.-A classic Snake game, inevitably a bit defective, please point out to everyone.

WinDriver9.0安装包。它支持windows XP/2000/98,Linux/WindowsCE.-WinDriver9.0 installation package. It supports windows XP/2000/98, Linux/WindowsCE.

一些视频图像处理中关于背景建模的论文（第2部分）-Some deal with video images on the background of modeling papers (Part 2)

thinkinc++(书，中文，源码)，初学者必备的一本好书-thinkinc++ (books, Chinese, source), beginners must have a good book