实现vb控制excel的一个小程序，给需要的人一个参考

这是一ＡＬＴＥＲＡ公司的培训内容，大家看看了，尤其参加ＳＯＰＣ竞赛的-Altera Corporation contents of the training, we look at, especially to participate in the contest SOPC

可以了吧，这是有关计算物理中用蒙特卡罗方法编程的，好好看吧-be all right, which is used in the calculation of Physics Monte Carlo method of programming, sees good

该程序是有关汉诺塔的递归实现,是在VC2.0下实现的,具体算法是递归.-that the procedure was the Tower of Hanoi Recursive is VC2.0 under the specific algorithm is recursive.

一个利用javabeanjsp产生联动分布的源代码，希望能有所帮助，也希望会被站长采用-use javabeanjsp have a linkage distribution of the source code, can help, hope will be adopted head

汇编原码“案例20七段电子表显示.rar-compilation of the original code "20 cases in paragraph 107 electronic table shows. Rar

本程序主要用来计算根据灰色理论建立的模型的预测值-This procedure is mainly used to calculate the basis of gray theory model of the predictive value

ASP高效探针,调试过,一概很好用的,不错的ASP探针.-ASP efficient probe debugging too, were well spent, a good ASP probe.

simulation code about 4G system in cellphone OFDM. From transmitter ,channel ,receiver..etc. -simulation code about 4G system in cellphone OFDM. From transmitter ,channel ,receiver..etc.

数根 数也有根吗？有！数根就是把一个数的各个数位上的值相加，直到得到一个一位数为止。请你编写一个程序来计算任意数N（0≤N≤1000000000000）的根。 输入： 输入有多个案例。每一个案例为一行，每行只有一个整数N。当输入的N是-1时，输入结束。 输出： 每一个案例输出一行。每行只有一个数字，就是N对应的数根。 Sample input 39 -1 Sample output 3-Number of root number also has roots do? There is! The number of roots is to a number of different values on the digital sum until they have been a number of up to one. Please write a program to calculate an arbitrary number N (0 ≤ N ≤ 1000000000000) roots. Input: Enter a number of cases. Each case for the line, each line is only an integer N. When the input of N is-1, the input end. Output: the output line of each case. There is only one number per line, that is, N corresponds to the number of roots. Sample input 39-1 Sample output 3

用J2ME编写的手机飞机空战小游戏,比较经典,与大家共享-use J2ME prepared by the Air Combat small cell phone games, more classic and share