一套交互和命令

在MATLAB环境中，用于实现线性方程组的快速运算，加快计算效率-Gauss method

该文件为c++的数学函数库!是一个非常有用的编程工具.它含有各种数学函数,为科学计算、工程应用等程序编写提供方便！-the document to the c Math Library! It is a very useful programming tools. It contains a variety of mathematical functions, for science, engineering application procedures for the preparation of convenience!

全国大学生飞思卡尔智能车比赛第八届摄像头组的程序，电机的控制，转向,对于初学者来说是一个很好的例程，而且不需要配置什么，历程包里已经都配置好，你只需要细心研读，努力努力，希望在智能车这条路上越走越好。

按照既定的步长，输入后筛选已有数据 程序3-accordance with the established step, the imported data screening procedures have been 3

资源描述CS7495 Final Project  Sooraj Bhat Object Removal by Exemplar-based Inpainting USING THE CODE Everything was done in Matlab and MEX (i.e. a C function callable from Matlab).  First, the C code needs to be compiled.  At the Matlab prompt, type:    mex bestexemplarhelper.c You should then be able to run the following (which takes ~2mins on my 2GHz Pentium 4 laptop with 256MB of RAM):    [i1,i2,i3,c,d,mov] = inpaint("bungee0.png","bungee1.png",[0 255 0]); A smaller run (~25 seconds) would be:    [i1,i2,i3,c,d,mov] = inpaint("bw0.png","bw2.png",[0 255 0]); To visualize:    plotall;    close; movie(mov); SAMPLE IMAGES & RESULTS *0.png      The original images ("bw" and "bungee") *{1,2}.png    The different fill region masks. *P2.png     &nbs

xml 解析的封装 xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装xml 解析的封装

使用lm算法对二维圆数据进行拟和，其中test_circle用于生成测试数据 fit2dcircle用于拟和 document.doc对算法原理进行详细说明 程序使用bcc5.60编译通过- Uses the lm algorithm to carry on for the two-dimensional round data draws up with, test_circle uses in to produce test data fit2dcircle to use in to draw up carries on the specify procedure with document.doc to the algorithm principle to use the bcc5.60 translation to pass

Numerical Anaysis 8th Edition, by Burden and Faires (Mathematica Source)

用差分方法求解沃尔泰拉方程，此处为一个变元的方程，由于该方程同时含有微分和积分，一般求解有一定的困难。-use of the finite difference method for Volterra equation here as a variable element of the equation, As the same time contain differential equations and integral, the general solution is definitely difficult.

tetsdftetsdftetsdftetsdftetsdftetsdftetsdftetsdff公司